--- In vpFREE@yahoogroups.com, ANN AND CHARLES GAUVIN
<ride3843@...> wrote:
> From: "mickeycrimm" <mickeycrimm@...>
> Never ask a loaded question if you don't already know the answer. I
> already know the answer, Harry.
> Where is the game? That's for me to know and everyone else to find
> out. Take care.
I taught middle school for 38 years. This reminds me of recess at middle
school. There was always one kid who had to throw down the gauntlet
at all
the others, who did not really care.... Annie, wishing the testosterone
count here were a little lower...
Being well into my 54th lap around the sun it's good to know I've got a little
testosterone left, My sentiments can be summed up in a line by Captain
Call in the great made-for-tv movie Lonesome Dove. After giving someone
a sound thrashing Call said "I detest insolence in a man, won't tolerate it."
As for my latest play, the 60 for one on Aces Full, and 80 for one on 4
Aces are the preset values. I'm actually playing the game with at least 120
bets into the Aces Full and and at least 240 bets into the 4 Aces.
I've think I have already explained on this site that thin edge video poker is
not my bag. All in all I'd rather play live poker than be a robot. Big fat
edges have been my specialty for 10 years. They are few and far in
between nowadays.
So I stumble onto this play. Since all my stuff is in storage in Las Vegas I
called a friend and got him to run the base payscale on Win, then crank out
the strategy on Strategy Master and mail it to me. This is where I started
on solving the puzzle. The base game is only 92.05% excluding the bonus
hands. The Aces hands are the key hands. So the hands involving no aces
have no strategy changes.
It's very easy to find the extra EV on hands like a dealt 4 aces or a dealt
aces full. For instance you will flop aces full every 9964 games (2,869,685
five card combinations divided by 288. The 288 is derived by multiplying 4
(combinations that make 3 aces) by 72 (the number of pairs other than
aces left in the deck). Then divide 51 ( 60 minus the 9 bets a normal full
house would pay) by 9964 and voila! You have an extra half percent in EV
on just that one scenario.
3 ace hands are easy too. A pair of aces is not that difficult either. But
the one-ace hands are where the work begins for someone doing all this
with a calculator like I did. There are 506,880 non-pair hands that have an
ace in them. Culling out the combinations that would play over the ace to
get the true frequency of playing one ace is boring, tedious, cumbersome
work to say the least.
Since I'm not qualified ( I quit school in the third grade when I got my
driver's license) I will defer to Mr. Dancer to give you the EV of this game.