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Wizard of Odds Strategy for 8-5 ACE$ Bonus Poker vs. regular 8-5 Bonus Poker

John, I believe you are correct that the only major change to the regular 8/5 BP strategy for 8/5 bonus ACES is to hold three aces in correct position instead of a dealt full house.

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--- In vpFREE@yahoogroups.com, "johnhunady"
<johnhunady@...> wrote:

Anyone out there dabble in creating a strategy for 8-5 ACE$
Bonus
Poker? This is an offshoot of 8-5 Bonus Poker, providing an
additional 4,000 coin bonus for 4 special aces arranged in
sequence,
either ACE$- or -ACE$. This game returns 99.41% compared to
99.17% for 8-5 Bonus Poker.

As instructed in Wizard of Odds, I took Jean Scott's
Frugal Video
Poker program and produced 5 different strategies using the
different
paybacks for 4 Aces, using 80 coins for Aces in wrong
position, 94
coins for NO Aces at all (basic 8-5 strategy), 110 coins
for 1 Ace in
position, 200 for 2 Aces in position and 440 for 3 Aces in
position.
Fine, that I did and I have 5 separate little strategies
for each of these ace positions.

But, am I right to presume that I need to use each strategy
SEPARATELY in conjunction with the 5 different Aces
positions, as
listed above in the Wizard of Odds link? Or is there is a
single
strategy that would combine all of these Ace positions?

Of interest, in comparing the 5 different strategies, the
only REAL
difference I see in play is when you have 3 Aces in
position vs. a
PAT Full House - there you would break up the Full House.
This
differs from the basic 8-5 Bonus Poker strategy. But with 2
Aces in
position you would keep the Full House, just like in 8-5
Bonus Poker.
I could be missing something, but this is what I am seeing.

Any feedback out there would really be great. I initially
assumed the
strategy for ACE$ Bonus Poker would be roughly the same as
8-5 Bonus
Poker, because catching the 4 aces in sequence (either
ACE$- or -ACE$)
is such a rare occurence.

John Hunady

John, I believe you are correct that the only major change to the

regular 8/5 BP strategy for 8/5 bonus ACES is to hold three aces in
correct position instead of a dealt full house.

> --- In vpFREE@yahoogroups.com, "johnhunady"
> <johnhunady@> wrote:
>
> Anyone out there dabble in creating a strategy for 8-5 ACE$
> Bonus
> Poker? This is an offshoot of 8-5 Bonus Poker, providing an
> additional 4,000 coin bonus for 4 special aces arranged in
> sequence,
> either ACE$- or -ACE$. This game returns 99.41% compared to
> 99.17% for 8-5 Bonus Poker.
>
> As instructed in Wizard of Odds, I took Jean Scott's
> Frugal Video
> Poker program and produced 5 different strategies using the
> different
> paybacks for 4 Aces, using 80 coins for Aces in wrong
> position, 94
> coins for NO Aces at all (basic 8-5 strategy), 110 coins
> for 1 Ace in
> position, 200 for 2 Aces in position and 440 for 3 Aces in
> position.
> Fine, that I did and I have 5 separate little strategies
> for each of these ace positions.
>
> But, am I right to presume that I need to use each strategy
> SEPARATELY in conjunction with the 5 different Aces
> positions, as
> listed above in the Wizard of Odds link? Or is there is a
> single
> strategy that would combine all of these Ace positions?
>
> Of interest, in comparing the 5 different strategies, the
> only REAL
> difference I see in play is when you have 3 Aces in
> position vs. a
> PAT Full House - there you would break up the Full House.
> This
> differs from the basic 8-5 Bonus Poker strategy. But with 2
> Aces in
> position you would keep the Full House, just like in 8-5
> Bonus Poker.
> I could be missing something, but this is what I am seeing.
>
> Any feedback out there would really be great. I initially
> assumed the
> strategy for ACE$ Bonus Poker would be roughly the same as
> 8-5 Bonus
> Poker, because catching the 4 aces in sequence (either
> ACE$- or -ACE$)
> is such a rare occurence.
>
> John Hunady

Hi Savorvpx,

Thanks for getting back to me. Yes, I think that is basically
correct, except maybe for a single Ace in the correct position with
another high card (J, Q, K) ..... then toss the other high card
(unless the same suit). For 2, 3, 4 Aces, the standard strategy
applies, except for a pat Full House with Aces as you confirmed.

Much Appreciated,
John Hunady

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--- In vpFREE@yahoogroups.com, savorvpx <savorvpx@...> wrote: