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Today I was dealt a Sequential Royal Flush!

What are the odds of getting the ACES 4 aces in ACES Bonus.

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To: vpF…@…com
From: alan3…@…com
Date: Wed, 13 Nov 2013 16:47:03 -0800
Subject: [vpFREE] RE: Today I was dealt a Sequential Royal Flush!

Thanks for the correction, I need to pay more attention to what I’m reading. That is pretty amazing.

—In vpf…@…com, <harry.porter@…> wrote:

Odds in the original post were for a DEALT sequential royal flush, ordered A-T

—In vpF…@…com, <alan3262@…> wrote:

Where do you get odds of 1 in 77,968,800 for a sequential royal flush? Not knowing exactly what game you were playing, let’s say the probability of a royal flush is 1 in 40,000. The probability that given a royal flush, it is sequential, is 1 in 60 (assuming that either A/K/Q/J/10 or 10/J/Q/K/A counts). Multiply the 2 numbers, and you get 1 in 2.4 million.

The 1/60 value assumes that you are not doing anything differently to get a sequential royal flush compared to trying to get any royal flush. I’m not clear if the jackpot required a sequential royal flush, or if it was for any royal flush. If it was only for a sequential, there would probably be some strategy adjustments if you had 2 or more royal flush cards in the right positions, so that might increase the chances slightly that a royal flush will be sequential.

If the progressive is for any royal flush, with a jackpot that high (I’m assuming your nickel machine required only 5 nickels for the jackpot of $545.15, which is over 2.7x the normal payout), you would probably be making major adjustments to your strategy in order to maximize EV, and these adjustments would increase the probability of a royal flush. For example, you would most likely always keep a high pair over 3 to a royal flush. In that case, your chances of getting a royal flush (including sequential royal flushes) would improve somewhat.

Too bad it was only in nickels! However it was a Progressive with 3x points .5% slot club. The EV was 100.3% today, that is why I was playing it. Dealt AKQJ10 hearts.

This is the one of the only 100+% opportunities in Deadwood, SD. Odds are 77,968,800 to one. But you already knew that!

Truly a once in a lifetime event for me, I am sure.

—In vpf…@…com, <neocacher@…> wrote:

With no strategy changes it would be 1 in 306,369.

The only strategy change I know of is to break a full house with three Aces in position.

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From: ken orgera <ken…@…com>
To: “vpF…@…com” <vpf…@…com>
Sent: Thursday, November 14, 2013 7:40 PM
Subject: RE: [vpFREE] RE: Today I was dealt a Sequential Royal Flush!

What are the odds of getting the ACES 4 aces in ACES Bonus.

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Thanks Howard, I got one last year at the Orleans after not getting a 4oak for 4 and 1/2 hours in fact I was complaining about it to another player when I hit it and didnot realize it till the machine kept ringing.

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To: vpF…@…com
From: pyi…@…net
Date: Fri, 15 Nov 2013 04:56:58 -0800
Subject: Re: [vpFREE] RE: Today I was dealt a Sequential Royal Flush!

With no strategy changes it would be 1 in 306,369.

The only strategy change I know of is to break a full house with three Aces in position.

From: ken orgera <ken…@…com>
To: “vpF…@…com” <vpf…@…com>
Sent: Thursday, November 14, 2013 7:40 PM
Subject: RE: [vpFREE] RE: Today I was dealt a Sequential Royal Flush!

What are the odds of getting the ACES 4 aces in ACES Bonus.

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Funny thing about this is that 8-5 ACES and 8-5 Bonus are on the same machines at one of the casinos I monitor and yes the 8-5 Bonus gets play on these.

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From: ken orgera <ken…@…com>
To: “vpF…@…com” <vpf…@…com>
Sent: Friday, November 15, 2013 8:13 PM
Subject: RE: [vpFREE] RE: Today I was dealt a Sequential Royal Flush!

Thanks Howard, I got one last year at the Orleans after not getting a 4oak for 4 and 1/2 hours in fact I was complaining about it to another player when I hit it and didnot realize it till the machine kept ringing.

With no strategy changes it would be 1 in 306,369.

The only strategy change I know of is to break a full house with three Aces in position.

From: ken orgera <ken…@…com>
To: “vpF…@…com” <vpf…@…com>
Sent: Thursday, November 14, 2013 7:40 PM
Subject: RE: [vpFREE] RE: Today I was dealt a Sequential Royal Flush!

What are the odds of getting the ACES 4 aces in ACES Bonus.

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To: vpFREE@yahoogroups.comFrom: pyiddy@att.netDate: Fri, 15 Nov 2013 04:56:58 -0800Subject: Re: [vpFREE] RE: Today I was dealt a Sequential Royal Flush!

Howard Stern wrote:

With no strategy changes it would be 1 in 306,369.
The only strategy change I know of is to break a full house with three Aces in position.

That's the main one with the aces at reset. There used to be
progressives that got high enough to make many changes, including
holding 2 aces over a full house, which brings the cycle down to
around 260,000. There are 2 other minor changes that I know of with
the aces at reset:

The best play for a hand which has an ace in the right position, a
high card which is offsuit with the ace and which blocks the
sequential aces, a ten which is offsuit with the ace, and 2 cards
below a ten which are offsuit with the ace is, assuming all 4 cards
besides the ace aren't suited and no 3 of them form a better straight
flush draw, to hold the ace.

The best play for a hand which has an ace in the right position, a
jack which is offsuit with the ace and which doesn't block the
sequential aces, a ten and a 2 through a 6 which are suited with the
jack, and a 2 through a 6 which are offsuit with the ace and the jack
is to hold the ace and the jack.

Ugh. An already complicated rule I gave needs modification.

This:

The best play for a hand which has an ace in the right position, a
high card which is offsuit with the ace and which blocks the
sequential aces, a ten which is offsuit with the ace, and 2 cards
below a ten which are offsuit with the ace is, assuming all 4 cards
besides the ace aren't suited and no 3 of them form a better straight
flush draw, to hold the ace.

Should be:

The best play for a hand which has an ace in the right position, a
high card which is offsuit with the ace and which blocks the
sequential aces, a ten which is offsuit with the ace, and 2 cards
below a ten which are offsuit with the ace is, assuming all 4 cards
besides the ace aren't suited, no 3 of them form a better straight
flush draw, there isn't a ten that's suited with a jack and there
isn't both a 9 and a 7, or there isn't a ten that's suited with a jack
which has a flush penalty and there is not a 7, 8, or 9, to hold the
ace.

On second thought, it's too complicated and worthless. It took me 20
minutes just to figure out how to word it. Forget it.