In a message dated 2/7/2003 4:31:51 PM Pacific Standard Time,
quadzilla666@earthlink.net writes:
Let's look at a simpler example. Suppose you gamble on
tossing a fair coin.Now let's add a 0.5% 'slot club' to the game.
This scenario is actually pretty similar to DB, but with
far less varianceIf you play 10$ a game and play 10 games, you will have
a very strong chance of losing (a little under 50%). You
will win 50 cents cashback, but that won't be enough to
change things.Now suppose you play this game 1,000,000 times. Now you
will receive $50,000 cashback. You will break even, or
better, if you manage to win at least 475,000 of the
games you play. It can be proved that winning fewer games
than this is HIGHLY unlikely.
While this is an excellent example, you lost a decimal place. At $10/toss,
you need to win at least 497,500 of the games you play to break even. Down
5000 games X $10/game = $50,000.
If we now play 10,000,000 times, we only need to win
4,750,000 hands to break even. That kind of result is
virtually impossible.
Likewise, lost a decimal again. You need to win 4,975,000 games to break
even, at $10/toss.
Variance is a factor.
Increasing the variance makes the probability of very extreme
results more likely. The impact on this situation is simply
to increase the number of hands one must play to be very sure of
being ahead. As an extreme case, a game like a lottery with a
high jackpot might take trillions of games to become 'certain'
of showing a profit.
A really good, easy to understand explanation.
Brian
[Non-text portions of this message have been removed]