vpFREE2 Forums

Super DDBP

#1

I saw an unusual game at the Rampart today ... or at least it seemed
unusual to me. I believe it was called Super DDBP.

The thing that made it unusual it that instead of "4 Aces with 2,3,4"
the hand was "4 Adjacent Aces", and instead of "4 2,3,4 w/A,2,3,4"
the hand was "4 Adjacent 2,3,4".

Is there anyway to calculate the return using WinPoker or FrugalVP?
My first reaction is no, even using the "customizing" feature.
Sometimes I wonder if the gamemakers create paytables like this
expressly for the purpose of making it difficult to determine the
return.

#2

Sure. Adjust the payoffs for quads using the following reasoning;

1. The "odd card" can appear in any of 5 positions.

2. If the odd card is in position 1 or 5 you have "adjacent" quads.
Lets assume these pay 2000 coins.

3. In positions 2,3,4 the quads are non-adjacent. This time, lets
assume a payoff of only 400 coins.

2 of 5 times it pays 2,000 = 4,000.
3 of 5 times it pays 400 = 1,200.
Total is 5,200
Average is 1,040

Set the payoff here, and compute the game's return.

What you cannot do is get correct strategy for any given hand. An
example would be "Do you break deuces full?"

In this game, 22KK2 is a different scenario than 222KK, the latter
hand potentially paying the 2,000 coin win.

Brian

···

--- brumar_lv <brumar_lv@yahoo.com> wrote:

I believe it was called Super DDBP.
The thing that made it unusual it that instead of "4 Aces with
2,3,4" the hand was "4 Adjacent Aces", and instead of "4 2,3,4
w/A,2,3,4" the hand was "4 Adjacent 2,3,4".

Is there anyway to calculate the return using WinPoker or FrugalVP?

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#3

<<<<<
Using your method the return is 98.67%. Thanks for the explanation.
Also, I should not have relied on my memory ... the actual name of
the game is Double BP Plus, as another poster already noted. For
those who may be interested, this is the pay schedule.
RF: 4000
SF: 250
Quad Aces (Adjacent): 2000
Quad 2,3,4 (Adjacent): 800
Quad Aces: 800
Quad 2,3,4: 400
Quad 5-King: 200
FH: 45
F: 30
Straight: 20
2Pair: 5
JB: 5

···

--- In vpFREE@yahoogroups.com, Brian Lavoie <blavoie46@y...> wrote:

Sure. Adjust the payoffs for quads using the following reasoning;

1. The "odd card" can appear in any of 5 positions.

2. If the odd card is in position 1 or 5 you have "adjacent" quads.
Lets assume these pay 2000 coins.

3. In positions 2,3,4 the quads are non-adjacent. This time, lets
assume a payoff of only 400 coins.

2 of 5 times it pays 2,000 = 4,000.
3 of 5 times it pays 400 = 1,200.
Total is 5,200
Average is 1,040

Set the payoff here, and compute the game's return.

What you cannot do is get correct strategy for any given hand. An
example would be "Do you break deuces full?"

In this game, 22KK2 is a different scenario than 222KK, the latter
hand potentially paying the 2,000 coin win.