I (naturally!) used Dunbar's Risk Analyzer for Video Poker v1.5 to
answer your FPDW risk-of-ruin question.
The chance of losing $5K in 45281 hands of $1 FPDW is 20%. But the
comparison should be to losing $4500, because losing $4500 is the
worst possible result from the tournament (if you assume $500 in
free play is very close to $500 in cash.)
The chance of losing $4.5K in 45281 hands of $1 FPDW is 24%. Here
is a table of possible outcomes:
DISTRIBUTION OF OUTCOMES
FINAL BANK, % CHANGE, PROBABILITY
0, lose 100%, 24%
1 - 899, lose 80% to 99%, 2%
900 - 1799, lose 60% to 80% 3%
1800 - 2699 , lose 40% to 60%, 4%
2700 - 3599, lose 20% to 40%, 5%
3600 - 4499, lose up to 20% , 6%
4500 - 5399, win up to 20%, 5%
5400 - 6299, win 20% to 40%, 6%
6300 - 7199, win 40% to 60%, 6%
7200 - 8099, win 60% to 80%, 6%
8100 - 8999, win 80% to 99+%, 5%
9000 +, double or more, 28%
This assumes no tipping, no errors, and no tax consequences (all of
which could be easily incorporated with DRA-VP. It also assumes
that you stop playing if at any point you have lost $4500.
--Dunbar
Right you are about the EV-- on 45281 hands of $1 FPDW its about
$1721
But what is the likelihood that you will lose $5K (1000 bets?)
playing that game (RoR given a
stake of $5000) Any idea?
I know that you have about 50% chance of losing $1600 (320 bets)
before playing even
15,000 hands-- but I hesitate to extrapolate.
My sense is that with $5K you have a decent chance of making it 1
RF cycle --anyone with
the data out there?-- but you have almost no chance of winning
$400K.
Anyone know where there is a $1 FPDW to try this on?
--- In vpFREE@yahoogroups.com, "Harry Porter" <harry.porter@>
wrote:
> To offer some perspective, the EV represented by the tournament
is
> less attractive than that presented by one RF cycle's play on $1
FPDW
···
--- In vpFREE@yahoogroups.com, "cdfsrule" <vpfree_digests@...> wrote:
> -- yet has considerably much more risk.
>
> As I note, that's merely a generalization.
>
> - Harry
>