Is your formula for average shockwave cycle correct?
Assuming quad cycle 382, I get:
(1/382) x1 + (1-1/382)(1/382) x2 + ... (1-1/382)^9 x10 /10 = 0.988301754
I looked at The Wizard of Odds site. This appears to be the
difference in
our evaluation. I estimated that the number of games in shockwave
mode was
9.99738. For brevity I used 10 because it only affected the third
decimal
place in the final ER. Could someone explain how 9.8836 is reached?
Using
optimum strategy for shockwave mode the quad cycle is 382.1705. I
determined
that 1/382.1705=.0026166. 10-.0026166= 9.99738
5-card
From: vpFREE@yahoogroups.com [mailto:vpF…@…com] On
Behalf Of
···
--- In vpFREE@yahoogroups.com, "5-card" <5-card@c...> wrote:
-----Original Message-----
jaydavidson118
Sent: Thursday, June 23, 2005 9:12 PM
To: vpFREE@yahoogroups.com
Subject: [vpFREE] Re: Shockwave Analysis "5-card"I finally looked at wizard of odds site, where he estimates the
expected number of hands in shockwave mode is 9.8836. This is the
flaw in the analysis below, you must subsitute 9.8836 for 10 in your
analysis, you will then get ev=99.553.