vpFREE2 Forums

question about faq

#1

from vpfree faq:
7. What is the long term? - Theoretically speaking, the long term
is forever. For video poker purposes, the long term is when you have
played a lot of hands (several million at a minimum) and actual
results are about the same as expected results. Tom Ski calculates
(with a 95% confidence factor) that the actual results for 10/7 DB,
played with perfect strategy, should be within 1.0% of expected
results after 1,085,465 hands, and within 0.1% after 108,546,482
hands.

I assume that by "within 1.0% of expected results" TomSki means 99.17%
to 101.17% return (100.17% +/-1%).

For 2sd (95%) at 1,085,465 hands I get 2sqrt(28/1,085,465)=.01 or 1%
which is the same result.

1% is a pretty big range in dollar terms, for 1,085,465 hands of 5
coin quarter play it represents $13,568

#2

from vpfree faq:
7. What is the long term? - Theoretically speaking, the long term is
forever. For video poker purposes, the long term is when you have played
a lot of hands (several million at a minimum) and actual results are
about the same as expected results. Tom Ski calculates (with a 95%
confidence factor) that the actual results for 10/7 DB, played with
perfect strategy, should be within 1.0% of expected results after
1,085,465 hands, and within 0.1% after 108,546,482 hands.

I assume that by "within 1.0% of expected results" TomSki means 99.17%
to 101.17% return (100.17% +/-1%).

Is your question whether or not your assumption is correct?

I assume the same as you do.

For 2sd (95%) at 1,085,465 hands I get 2sqrt(28/1,085,465)=.01 or 1%
which is the same result.

This seems to confirm Tom Ski's figure and your assumption.

1% is a pretty big range in dollar terms, for 1,085,465 hands of 5
coin quarter play it represents $13,568

Yep.

···

On 12 Apr 2005 at 7:27, nightoftheiguana2000 wrote:

#3

> from vpfree faq:
> 7. What is the long term? - Theoretically speaking, the long

term is

> forever. For video poker purposes, the long term is when you have

played

> a lot of hands (several million at a minimum) and actual results

are

> about the same as expected results. Tom Ski calculates (with a 95%
> confidence factor) that the actual results for 10/7 DB, played

with

> perfect strategy, should be within 1.0% of expected results after
> 1,085,465 hands, and within 0.1% after 108,546,482 hands.

> I assume that by "within 1.0% of expected results" TomSki means

99.17%

> to 101.17% return (100.17% +/-1%).

Is your question whether or not your assumption is correct?

Yes. The other way to read this is that the results would be within 1%
of +.17%, i.e. +.168% to +.172%. That would be incorrect.

The term "expected results" is ambiguous. Is an even gamble 0 or 100%?

I assume the same as you do.

> For 2sd (95%) at 1,085,465 hands I get 2sqrt(28/1,085,465)=.01 or

1%

···

--- In vpFREE@yahoogroups.com, "vpFREE" <vpFREE@C...> wrote:

On 12 Apr 2005 at 7:27, nightoftheiguana2000 wrote:
> which is the same result.

This seems to confirm Tom Ski's figure and your assumption.

> 1% is a pretty big range in dollar terms, for 1,085,465 hands of 5
> coin quarter play it represents $13,568

Yep.