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Proper hold JOB 3 card royal vs. 4 card flush?????

You're making faulty assumptions in your Kelly calculation.

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On Mon, Sep 15, 2014 11:26 AM PDT nightoftheiguana2000@yahoo.com [vpFREE] wrote:

At the risk of beating a dead horse, another option is the Kelly strategy.

To get Kelly strategy at a 1 Royal bankroll (=800 bets), set the Royal to 554 in the strategy generator.

To get Kelly strategy at a 2 Royal bankroll, set the Royal to 648 in the strategy generator.

To get Kelly strategy at a 3 Royal bankroll, set the Royal to 690 in the strategy generator.

To get Kelly strategy at a 5 Royal bankroll, set the Royal to 729 in the strategy generator.

To get Kelly strategy at a 10 Royal bankroll, set the Royal to 762 in the strategy generator.

To get Kelly strategy at a 100 Royal bankroll, set the Royal to 795 in the strategy generator.

Above roughly a 100 Royal bankroll, Kelly strategy is virtually the same as maxEV strategy. Included in Kelly strategy is the tactic of not betting at all once your current bankroll falls below the Kelly threshold which is roughly variance/edge bets.

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Adjusted Kelly Win = (ln(BR+Win-1)-ln(BR))/(ln(BR+1)-ln(BR))

OK, but if you look at the Certainty Equivalence you get something like Bankroll > 33 Royals to hold this 3 card royal over this 4 card flush.

In case anyone wants to double check the numbers:

hand: AJT9s8o

hold AJTs:
outs: 1rf,35fl,15st,9-3k,27-2p,240hp
EV=1.2867715 VAR=592.17308

hold AJT9s:
outs: 9fl,6hp
EV=1.2765957 VAR=5.3915799

Certainty Equivalent = EV - VAR/2xBankroll

For Bankroll < 28,832 bets (about 36 royals), AJT9s has a higher Certainty Equivalent

nightoftheiguana2000@yahoo.com wrote:

In case anyone wants to double check the numbers:

hand: AJT9s8o

hold AJTs:
outs: 1rf,35fl,15st,9-3k,27-2p,240hp
EV=1.2867715 VAR=592.17308

hold AJT9s:
outs: 9fl,6hp
EV=1.2765957 VAR=5.3915799

Certainty Equivalent = EV - VAR/2xBankroll

For Bankroll < 28,832 bets (about 36 royals), AJT9s has a higher Certainty Equivalent

I compared the Kelly formulas and got 28,298 units as the bankroll
that equates them.

For Bankroll < 28,832 bets (about 36 royals), AJT9s has a higher Certainty Equivalent [than AJTs]

I compared the Kelly formulas and got 28,298 units as the bankroll

that equates them.

Close enough in my book, there’s obviously some precision issue but personally that doesn’t really bother me.

Some gamblers might be asking: “Why should I care about the Kelly system?”

Well, you should care, a lot, if you care how many hands it takes to double your bankroll.

The Kelly Criterion - Wizard of Odds

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The Kelly Criterion - Wizard of Odds
The Wizard of Odds on the Kelly Criterion.

View on wizardofo…

Preview by Yahoo

Holding the four clubs: EV = 1.2766
Holding 3 to the royal: EV = 1.2868

You would have to play an awful lot of hands for that small difference to matter.

When the EV is this close, relative volatility is more important than EV. I don’t know how Winpoker computes, but it seems obvious that drawing one card to a flush is way less volatile than going for the royal. It’s a matter of bankroll survival.

Ignoring small possible contributions by a high pair:
Probabilities:
One card flush draw: 9/47
Two card royal draw: (2/47)(1/46)
Ratio: 207:1 in favor of the one card draw to a flush.

    • Norma

The EV depends on what the 3 royal cards are.

The 4th suited card changes value if it is a 4-card SF.

KQJ = 1.4829

AK10 = 1.2868

5-card

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From: vpF…@…com [mailto:vpF…@…com]
Sent: Sunday, September 28, 2014
7:16 PM
To: vpF…@…com
Subject: [vpFREE] Re: Proper hold
JOB 3 card royal vs. 4 card flush???

Holding
the four clubs: EV = 1.2766

Holding 3 to the royal: EV = 1.2868

You would have to play an awful lot of hands for that small difference to
matter.

When the EV is this close, relative volatility is more important than EV. I
don’t know how Winpoker computes, but it seems obvious that drawing one card to
a flush is way less volatile than going for the royal. It’s a matter of
bankroll survival.

Ignoring small possible contributions by a high pair:

Probabilities:

One card flush draw: 9/47

Two card royal draw: (2/47)(1/46)

Ratio: 207:1 in favor of the one card draw to a flush.

    • Norma

That’s correct.
I used the cards as stated in the original posted question.

    • Norma

Norma wrote: Holding the four clubs: EV = 1.2766
Holding 3 to the royal: EV = 1.2868

You would have to play an awful lot of hands for that small difference to matter.

When
the EV is this close, relative volatility is more important than EV. I don’t know how Winpoker computes, but it seems obvious that drawing one card to a flush is way less volatile than going for the royal. It’s a matter of bankroll survival.

Ignoring small possible contributions by a high pair:
Probabilities:
One card flush draw: 9/47
Two card royal draw: (2/47)(1/46)
Ratio: 207:1 in favor of the one card draw to a flush.

···

Your conclusion is defensible, maybe, but the way you got there was questionable.

The difference between the plays is about 5 cents for the 5-coin dollar player. Or 1 cent for the quarter player. Or $5 for the $100 player. Multiply those numbers accordingly if you’re playing Triple Play, Five Play, etc. Whether that’s a lot or a little can be argued. On a personal basis, a 5 cent error for dollar 5-coin players is HUGE. I suppose you could say I play “an awful lot of hands”

You’re comparing the frequency of a flush (worth 30 coins) with the frequency of a royal flush (worth 4,000 coins). You are looking at how often something happens rather than how much it pays. Even if you accept that as reasonable methodology, why do you count the number of 30-coin flushes when you’re drawing one card and not count the number of 30-coin flushes and 20-coin straights when you’re drawing two cards? Instead of 1-out-of-1081 chances to get a royal from AKT, you get 51-chances-out-of-1081 to get a royal, flush, or straight. Big difference.

I’m not sure why you neglect high pairs. You get a high pair from AKT about 22% of the time. You get a high pair from AKT4 less than 13% of the time,which is slightly more than half as often. I know a high pair is small compared to a flush, but not nearly as much smaller as a flush is to a royal flush.

When it comes down to how often do you get ANYTHING POSITIVE from the two draws, it’s 30% of the time from AKT and 32% of the time from AKT4. While these numbers aren’t identical, they are nowhere near as different as the 207-1 ratio you cited in your post.

Bankroll preservation is an essential part of intelligent gambling — which is your main point, and you’re correct in this. But if you’re regularly making safety plays this large, you have no chance to be playing a positive game no matter how large the slot club is.

Bob

I think that the one factor that both of you are missing is the frequency of the situation.

On average how often does this situation come up ?

I’m guessing it’s not too often.

If I am correct then the whole argument is akin to discussing how many angels can dance on the head of a pin.

Worrying about losing 5 cents on a play is not really that important when the play happens once a day, but it is very important if it happens 20 times an hour.

A.P.

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From: “Bob Dancer bobdance…@…com [vpFREE]” <vpF…@…com>
To: “vpf…@…com” <vpf…@…com>
Sent: Monday, September 29, 2014 4:43 PM
Subject: RE: [vpFREE] Re: Proper hold JOB 3 card royal vs. 4 card flush???

Norma wrote: Holding the four clubs: EV = 1.2766
Holding 3 to the royal: EV = 1.2868

You would have to play an awful lot of hands for that small difference to matter.

When
the EV is this close, relative volatility is more important than EV. I don’t know how Winpoker computes, but it seems obvious that drawing one card to a flush is way less volatile than going for the royal. It’s a matter of bankroll survival.

Ignoring small possible contributions by a high pair:
Probabilities:
One card flush draw: 9/47
Two card royal draw: (2/47)(1/46)
Ratio: 207:1 in favor of the one card draw to a flush.

Your conclusion is defensible, maybe, but the way you got there was questionable.

The difference between the plays is about 5 cents for the 5-coin dollar player. Or 1 cent for the quarter player. Or $5 for the $100 player. Multiply those numbers accordingly if you’re playing Triple Play, Five Play, etc. Whether that’s a lot or a little can be argued. On a personal basis, a 5
cent error for dollar 5-coin players is HUGE. I suppose you could say I play “an awful lot of hands”

You’re comparing the frequency of a flush (worth 30 coins) with the frequency of a royal flush (worth 4,000 coins). You are looking at how often something happens rather than how much it pays. Even if you accept that as reasonable methodology, why do you count the number of 30-coin flushes when you’re drawing one card and not count the number of 30-coin flushes and 20-coin straights when you’re drawing two cards? Instead of 1-out-of-1081 chances to get a royal from AKT, you get 51-chances-out-of-1081 to get a royal, flush, or straight. Big difference.

I’m not sure why you neglect high pairs. You get a high pair from AKT about 22% of the time. You get a high pair from AKT4 less than 13% of the time,which is slightly more than half as often. I know a high pair is small compared to a flush,
but not nearly as much smaller as a flush is to a royal flush.

When it comes down to how often do you get ANYTHING POSITIVE from the two draws, it’s 30% of the time from AKT and 32% of the time from AKT4. While these numbers aren’t identical, they are nowhere near as different as the 207-1 ratio you cited in your post.

Bankroll preservation is an essential part of intelligent gambling — which is your main point, and you’re correct in this. But if you’re regularly making safety plays this large, you have no chance to be playing a positive game no matter how large the slot club is.

Bob

I agree with Albert that the overall cost is extremely small when individual cost is small and the play is rare.

We’re talking about the specific 3-card RF of Ace, Ten, with a J, Q or K.

When we have that hand in JOB, holding the 4th flush card costs 1% of our bet. (5 cents on a $5 bet.) How often do we get the hand?

I think we get that hand about 0.1% of the time. (my calc is shown below)

So, by keeping the 4th flush card, we will lower our EV by 1% of 0.1% of our total bets. For every $1 million we bet, we give up $10 in EV by holding the 4th flush card.

How did I get the 0.1% figure? I’m going to take the time to write it out because (1) if I’ve done it correctly, it may help someone do similar calc’s, and (2) if I’m wrong, I want to know where!

So, here goes: How many ways are there to get a hand with A, T, another RF card, and a 4th suited card?

Say I want to know the chance of getting 5 cards in this order:

Ace, Ten, otherRFcard, other suited card, other non-suited card

Card Ways Why

Ace 4 4 suits to choose from

Ten 1 has to be same suit

OtherRF card 3 can be J, Q, or K of same suit

4th flush card 8 can only be 2-9, same suit

5th card 27 can be 2-10 of any different suit

To get the total number of ways to deal out a hand in that order, you multiply the “Ways”. 4 * 1 * 3 * 8 * 27 = 2592

But we don’t care what order the cards are in, so we have to figure out how many ways the 5 cards can be ordered.

There are 5 ways to pick which card will be 1st, 4 ways to pick the 2nd card, 3 ways to pick the 3rd card, 2 ways to pick the 4th card, and just 1 way to pick the 5th card. Multiplying 54321 makes 120 ways to order the five different cards.

So, the total number of ways to be dealt a hand with A,T,(J,Q,or K), small suited, and small non-suited is 2592 * 120 = 311,040.

That seems like a lot, but it’s a small fraction of the 52 * 51 * 50 * 49 * 48 ways to deal out ANY five cards. That number is 311,875,200.

Therefore, the chance of being dealt a 3-card RF with A,T with a 4th small (2-9) flush card and a small (2-10) non-suited card is 311,040 / 311,875,200.= 0.1%

And the total cost of holding the 4th flush card on that hand is 1% of 0.1% = 0.001% of your total bet.

I’m not endorsing holding the 4th flush card as a general play in JOB. As “5-card” mentioned, the cost is much bigger on other 3-card RF’s. The Ace/Ten 3-card RF’s are only a small fraction of the total times you might have a 3-card RF with a 4th flush card.

–Dunbar

—In vpF…@…com, <ehpee@…> wrote :

I think that the one factor that both of you are missing is the frequency of the situation.

On average how often does this situation come up ?

I’m guessing it’s not too often.

If I am correct then the whole argument is akin to discussing how many angels can dance on the head of a pin.

Worrying about losing 5 cents on a play is not really that important when the play happens once a day, but it is very important if it happens 20 times an hour.

A.P.

···

From: “Bob Dancer bobdancervp@… [vpFREE]” <vpF…@…com>
To: “vpf…@…com” <vpf…@…com>
Sent: Monday, September 29, 2014 4:43 PM
Subject: RE: [vpFREE] Re: Proper hold JOB 3 card royal vs. 4 card flush???

Norma wrote: Holding the four clubs: EV = 1.2766
Holding 3 to the royal: EV = 1.2868

You would have to play an awful lot of hands for that small difference to matter.

When
the EV is this close, relative volatility is more important than EV. I
don’t know how Winpoker computes, but it seems obvious that drawing one
card to a flush is way less volatile than going for the royal. It’s a
matter of bankroll survival.

Ignoring small possible contributions by a high pair:
Probabilities:
One card flush draw: 9/47
Two card royal draw: (2/47)(1/46)
Ratio: 207:1 in favor of the one card draw to a flush.

Your conclusion is defensible, maybe, but the way you got there was questionable.

The difference between the plays is about 5 cents for the 5-coin dollar player. Or 1 cent for the quarter player. Or $5 for the $100 player. Multiply those numbers accordingly if you’re playing Triple Play, Five Play, etc. Whether that’s a lot or a little can be argued. On a personal basis, a 5
cent error for dollar 5-coin players is HUGE. I suppose you could say I play “an awful lot of hands”

You’re comparing the frequency of a flush (worth 30 coins) with the frequency of a royal flush (worth 4,000 coins). You are looking at how often something happens rather than how much it pays. Even if you accept that as reasonable methodology, why do you count the number of 30-coin flushes when you’re drawing one card and not count the number of 30-coin flushes and 20-coin straights when you’re drawing two cards? Instead of 1-out-of-1081 chances to get a royal from AKT, you get 51-chances-out-of-1081 to get a royal, flush, or straight. Big difference.

I’m not sure why you neglect high pairs. You get a high pair from AKT about 22% of the time. You get a high pair from AKT4 less than 13% of the time,which is slightly more than half as often. I know a high pair is small compared to a flush,
but not nearly as much smaller as a flush is to a royal flush.

When it comes down to how often do you get ANYTHING POSITIVE from the two draws, it’s 30% of the time from AKT and 32% of the time from AKT4. While these numbers aren’t identical, they are nowhere near as different as the 207-1 ratio you cited in your post.

Bankroll preservation is an essential part of intelligent gambling — which is your main point, and you’re correct in this. But if you’re regularly making safety plays this large, you have no chance to be playing a positive game no matter how large the slot club is.

Bob

I’d count the offsuit high cards, such as a hand like AQT4sK, so that your 27 should be a 33.

I agree with Albert that the overall cost is extremely small when individual cost is small and the play is rare.

We’re talking about the specific 3-card RF of Ace, Ten, with a J, Q or K.

When we have that hand in JOB, holding the 4th flush card costs 1% of our bet. (5 cents on a $5 bet.) How often do we get the hand?

I think we get that hand about 0.1% of the time. (my calc is shown below)

So, by keeping the 4th flush card, we will lower our EV by 1% of 0.1% of our total bets. For every $1 million we bet, we give up $10 in EV by holding the 4th flush card.

How did I get the 0.1% figure? I’m going to take the time to write it out because (1) if I’ve done it correctly, it may help someone do similar calc’s, and (2) if I’m wrong, I want to know where!

So, here goes: How many ways are there to get a hand with A, T, another RF card, and a 4th suited card?

Say I want to know the chance of getting 5 cards in this order:

Ace, Ten, otherRFcard, other suited card, other non-suited card

Card Ways Why

Ace 4 4 suits to choose from

Ten 1 has to be same suit

OtherRF card 3 can be J, Q, or K of same suit

4th flush card 8 can only be 2-9, same suit

5th card 27 can be 2-10 of any different suit

To get the total number of ways to deal out a hand in that order, you multiply the “Ways”. 4 * 1 * 3 * 8 * 27 = 2592

But we don’t care what order the cards are in, so we have to figure out how many ways the 5 cards can be ordered.

There are 5 ways to pick which card will be 1st, 4 ways to pick the 2nd card, 3 ways to pick the 3rd card, 2 ways to pick the 4th card, and just 1 way to pick the 5th card. Multiplying 54321 makes 120 ways to order the five different cards.

So, the total number of ways to be dealt a hand with A,T,(J,Q,or K), small suited, and small non-suited is 2592 * 120 = 311,040.

That seems like a lot, but it’s a small fraction of the 52 * 51 * 50 * 49 * 48 ways to deal out ANY five cards. That number is 311,875,200.

Therefore, the chance of being dealt a 3-card RF with A,T with a 4th small (2-9) flush card and a small (2-10) non-suited card is 311,040 / 311,875,200.= 0.1%

And the total cost of holding the 4th flush card on that hand is 1% of 0.1% = 0.001% of your total bet.

I’m not endorsing holding the 4th flush card as a general play in JOB. As “5-card” mentioned, the cost is much bigger on other 3-card RF’s. The Ace/Ten 3-card RF’s are only a small fraction of the total times you might have a 3-card RF with a 4th flush card.

–Dunbar

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----- h_dun…@…com [vpFREE] <vpF…@…com> wrote:

007 wrote: I’d count the offsuit high cards, such as a hand like AQT4sK, so that your 27 should be a 33.

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I wouldn’t count such a hand because we’re looking for when the 4-card flush is an error rather than the correct play. In the hand 007 cited, holding the 4-card flush would be correct.

More important than how much this particular play is worth is what other hands fall into the “bankroll preservation is more important than EV” discussion. Each “safety play” may be small in cost, but if there are a lot of them, it can add up.

Bob

In that case, the ten should be eliminated, also, so the 27 should be a 24.

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----- Bob Dancer bobdance…@…com [vpFREE] <vpF…@…com> wrote:

007 wrote: I’d count the offsuit high cards, such as a hand like AQT4sK, so that your 27 should be a 33.


I wouldn’t count such a hand because we’re looking for when the 4-card flush is an error rather than the correct play. In the hand 007 cited, holding the 4-card flush would be correct.

More important than how much this particular play is worth is what other hands fall into the “bankroll preservation is more important than EV” discussion. Each “safety play” may be small in cost, but if there are a lot of them, it can add up.

Bob