vpFREE2 Forums

penalty cards

From: Steve Jacobs <jacobs@xmission.com>

Yes, it is theoretically possible to have more than one strategy (and
I've seen real world examples of this for max-EV strategy), but this
is a fine point that doesn't happen all that often with real games.

With one notable exception:

In FPDW, drawing to a 3 card double inside straight flush with an inside penalty has exactly the same EV as drawing to a 4 card inside straight, but obviously with a different distribution of payoff outcomes.

Whle the overall effect on the variance of the game is tiny, if one were trying to minimize variance, they'd choose the inside straight draw over the SF draw in this one case.

···

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I wasn't aware of this case, thanks for mentioning it.

I had to dig through some old files to find the case that I had in
mind. It is JoB with payoffs of 500/100/35/10/7/6/3/1/1 units.
For this game, if you are dealt Jd Td 9d 8d 7c, then standing
pat with a straight has the same EV as drawing to a 4 card
straight-flush. This case is especially interesting because the
EV is exactly 6 units. This is a lousy game though, so this
curiosity my be its only redeeming feature.

···

On Thursday 08 December 2005 09:52 pm, Part Timer wrote:

From: Steve Jacobs <jacobs@xmission.com>

>Yes, it is theoretically possible to have more than one strategy (and
>I've seen real world examples of this for max-EV strategy), but this
>is a fine point that doesn't happen all that often with real games.

With one notable exception:

In FPDW, drawing to a 3 card double inside straight flush with an inside
penalty has exactly the same EV as drawing to a 4 card inside straight, but
obviously with a different distribution of payoff outcomes.

Whle the overall effect on the variance of the game is tiny, if one were
trying to minimize variance, they'd choose the inside straight draw over
the SF draw in this one case.

Part timer noted: With one notable exception:

In FPDW, drawing to a 3 card double inside straight flush with an inside

penalty has exactly the same EV as drawing to a 4 card inside straight,
but
obviously with a different distribution of payoff outcomes.

Whle the overall effect on the variance of the game is tiny, if one were

trying to minimize variance, they'd choose the inside straight draw over
the
SF draw in this one case.

There are more exceptions than just the one you mention in FPDW. In the
99.92% 2PJW, a 4-card flush with a joker and a 4-card inside straight
with the joker have the same EV (such as from W "35K"6). There are other
examples from other games, but they are rare.

Without an extra post, I agree with Part Timer's correction of my 1,296
to 243 lines in Spin Poker Deluxe.

Bob Dancer

For the best in video poker information, visit www.bobdancer.com
or call 1-800-244-2224 M-F 9-5 Pacific Time.

Has anyone analyzed the "Ace Invaders" game that is on LED's website. It's fun to play, in fact I got 5 aces after a few hands. Should you always hold aces? And what is the strategy/payback?

Has anyone analyzed the "Ace Invaders" game that is on LED's

website. It's

fun to play, in fact I got 5 aces after a few hands. Should you

always hold

aces? And what is the strategy/payback?

Dick, I believe the only times you throw an ace away in Ace Invaders
is when going for a four card Straight Flush or a Royal Flush.

···

--- In vpFREE@yahoogroups.com, "Dick Kalagher" <rkalagher@c...> wrote:

Has anyone analyzed the "Ace Invaders" game that is on LED's

website. It's

fun to play, in fact I got 5 aces after a few hands. Should you

always hold

aces? And what is the strategy/payback?

Dick, I believe the only times you throw an ace away in Ace Invaders
is when going for a four card Straight Flush or a Royal Flush.

···

--- In vpFREE@yahoogroups.com, "Dick Kalagher" <rkalagher@c...> wrote:

So it seems that IS possible to have more than one equivalent optimal
stratgey even for max-EV. [Aside: one could still argue that this was
not the case; that instead, there must be one, and only 1 optinmal max-
EV strategey, and that this stragtegy was a super-set of the all the
other optimal stragtegies. While that may seem to be a reasonable
argument for max-EV, it doesn't hold in general. Let's save that issue
for another thread.]

Max-EV stratgeies belong to a partiucally simple class of possible
strategies whose goal is optimize a criteria that depends only on the
particualr hand. For example, in max-EV, your corrent bankroll
doesn't effect the stratgey. Indeed, nonething but the cards dealt to
you (and the rules of the game) affect the play (strategy).
Nonetheless, though rare, there was/is the possibility of mulitple
equivelent optimal stretgies!

Now, what happens in more complicated case, like min-cost-royal or min-
RoR? Is the existance of equivalendt optimal stratgies still rare?
Certainly not min-RoR for JoB... in this case every stratgey is
equivelenty optimal! Ok, that's kind of a silly example. But it makes
an important point: one can't be sure that someone's min-cost royal
(or whatever) strategy is the only "optimal" strategy, assuming, of
coarse that said strategy was formulated without error. Saying
otherwise ("this is the optimal stratgey for such and such and all
other strategies are therefore either in error or non-optimal") to me,
is pretty much (logically) equivalent to saying "max_EV strategy is the
only valid strategy"... which I beleive isn't the case.

I surely don't want to water-down the "EV isn't eveything" argument, so
unless I can prove that a certain stratey is the ONLY optimal strategy,
I'm going to avoid claiming so (or suggesting so), and I'd hope others
here (who also know that EV isn't everything) do the same. Deal?

···

---------------------------------------------------------------
In vpFREE@yahoogroups.com, Steve Jacobs <jacobs@x...> wrote:
Wed Dec 7, 2005 10:43 pm:

For a player who truly wishes to maximize the probability of hitting
a royal before losing their current bankroll, the min-RoRBR strategy is
exactly optimal, mathematically speaking, for this very purpose. Any
other strategy will increase the probability that the player will go
broke rather than survive to hit a royal flush.

So it seems that IS possible to have more than one equivalent optimal
stratgey even for max-EV. [Aside: one could still argue that this was
not the case; that instead, there must be one, and only 1 optinmal max-
EV strategey, and that this stragtegy was a super-set of the all the
other optimal stragtegies. While that may seem to be a reasonable
argument for max-EV, it doesn't hold in general. Let's save that issue
for another thread.]

Specific examples of multiple strategies have already been posted for
max-EV. I've never seen such an example for other types of strategies,
but it isn't something that I spend much time looking for. I believe they
are about as likely to occur in alternate strategies as they are in max-EV
strategies, because the method I use to find optimal strategies is based
on maximizing "virtual EV" based on a "virtual payoff schedule."

Max-EV stratgeies belong to a partiucally simple class of possible
strategies whose goal is optimize a criteria that depends only on the
particualr hand. For example, in max-EV, your corrent bankroll
doesn't effect the stratgey. Indeed, nonething but the cards dealt to
you (and the rules of the game) affect the play (strategy).
Nonetheless, though rare, there was/is the possibility of mulitple
equivelent optimal stretgies!

I would call these "fixed strategies". Min-risk, min-cost and min-RoRBR
are fixed strategies, as are strategies that minimize average loss between
a particular payoff. But log-optimal strategy varies with bankroll, and the
strategy that maximizes the probability of reaching a fixed dollar bankroll
before going broke varies based on distance from the goal (at least, for
VP games).

Now, what happens in more complicated case, like min-cost-royal or min-
RoR? Is the existance of equivalendt optimal stratgies still rare?
Certainly not min-RoR for JoB... in this case every stratgey is
equivelenty optimal!

You didn't even bother to read my last post, did you. I really don't like
repeating myself but THAT IS WRONG.

Ok, that's kind of a silly example.

Not as silly as ignoring everything that I wrote about what risk "means"
in a negative game.

But it makes
an important point: one can't be sure that someone's min-cost royal
(or whatever) strategy is the only "optimal" strategy, assuming, of
coarse that said strategy was formulated without error.

Nonsense. If this was something that was important to me, rather than
merely an amusing curiosity, I could easily modify my program to identify
all cases that have more than one choice for the optimal play.

In the rare cases when multiple strategies happen, they involve a small
number of cases where the hand can be played in more than one way
without changing the overall performance. The differences in the strategies
are minor curiosities, not massive glaring differences. In publishing terms,
they might merit footnotes, but certainly not an appendix.

Saying
otherwise ("this is the optimal stratgey for such and such and all
other strategies are therefore either in error or non-optimal") to me,
is pretty much (logically) equivalent to saying "max_EV strategy is the
only valid strategy"... which I beleive isn't the case.

Those statements aren't logically equivalent at all. Not remotely.
I think you might be missing a really key point here. Optimal is _always_
relative to the player's objective. You can't really answer the question
"what is the best way to play" until you first answer the question "best
in what sense -- how do you wish to measure performance". So, a game
can have multiple (equivalent) max-EV strategies, but that does not imply
that optimizing other metrics will lead to multiple strategies. For example,
the min-risk strategy for a given game is likely to be unique even if the
game allows multiple max-EV strategies.

Also, the fact that a given metric leads to a unique strategy does _not_
imply that the strategy is unique to that one metric. Sometimes the same
strategy will be optimal for more than one metric. A specific example
comes from 10/7 Double Bonus. If, for some odd reason, a player wants
to maximize the average loss between payoffs for small quads (the ones
that pay 80 units), then the optimal strategy just happens to be identical
to max-EV strategy.

I surely don't want to water-down the "EV isn't eveything" argument, so
unless I can prove that a certain stratey is the ONLY optimal strategy,
I'm going to avoid claiming so (or suggesting so), and I'd hope others
here (who also know that EV isn't everything) do the same. Deal?

Do as you like. I'm not going to point out every niggly exception to
every statement that I make. Sometimes I qualify my statements,
sometimes I don't, but almost any simple statement of VP fact has
exceptions if one digs deep enough. If it brings you pleasure to point
them out, then by all means do so.

You also didn't answer my question. Are you a physicist, or was
your reference to "Feynman path integrals" just tossed out as some
form of "name dropping"?

···

On Saturday 10 December 2005 02:09 pm, cdfsrule wrote:

It is true that one must usually trade off ER in order to optimize something
else. However, that door swings both ways. From the perspective of
someone who wishes to minimize risk, they would have to accept an
increased risk in order to achieve greater ER. So, no matter what metric
one chooses to optimize, there will be many other things traded off in order
to squeeze out every last bit of the chosen metric.

···

On Sunday 11 December 2005 08:50 am, mklpryy24 wrote:

---
All of the stratergies dicussed so far compromise ethier the total
return or the volatility or both whether it is min-risk, ror, max-
royal, Kelley bet, martingale( for Harry), or what i do ignore
penalty cards .
That is a fact, & i can live with it.

mklpryy24 wrote:

Since optimal is singular, the can only be 1 optimal stratergy for
each goal.

Grammatically, "optimal" modifies either single or plural nouns - it
has no number.

You're correct in that there tends to be only one optimal strategy for
a given goal. There are cases where more than one strategy achieves a
specific goal with equal strength, in which case all such strategies
are optimal.

It's important to bear in mind that optimality is defined by a related
goal. Thus, for any subject matter, there may be multiple optimal
strategies, each of which targets a different goal. There are unique
goals associated with each of the discussion topics identified in the
full text of your post.

- H.

While I don't consider myself a physicist, I have worked as one for few years. (Does tht
make me a "professional physicist?" ) My degree is in Physical Chemistry, not Physics, and
at one time I was an expert on some obscure areas of quantum physics/optics. While I
have never taught a coarse on Feynman path integrals, I have covered that subject in
other classes I have taught. Perhaps ten years ago I could have handled (without help) a
renomalization problem using Feynman's approach, but not today. I do know where to
find the help I need if I had to solve such a problem today, though. But, I feel quite
strongly that my qualifications (or lack there-of) shouldn't matter to you. Rather than
'simply beleiving what I say/write or not', I'd hope that you could convince yourself of
things or perhaps ask questions where you need help.

Back to my point: IN GENERAL, OPTIMIZATION PROBLEMS CAN HAVE MORE THAN ONE
EQUIVALENTLY OPTIMAL SOLUTION OR NO SOLUTION. That is, any number of equivelent
solutions including zero. Optimal solutions can be "local" or "global" (locally optimal or
globally optimal) and there may be more than 1 global "optimal solution", though each
solution (to be optimal) must have the same "optimal value" (you can find definitions of
these terms at: http://www.nist.gov/dads/HTML/optimization.html ). In general, the
statement "that since X is an optimal solution to the problem, all other solutions are non-
optimal" just isn't true.

So either you just don't beleive these mathematical facts (if I may borrow your usage) or
you don't think it applies to your strategies. I could go ahead and write a long tutorial on
this subject, complete with references, etc., trying (likely in vane) to persuade you
otherwise. Or you could, I guess, save me the effort, and show how I got the facts wrong
or how they don't apply to you. You might also show, through enumertion and evaluation
of all other posible strategies, that yours is indeed the only optimal one, surely a painful if
not imporssible task. (See http://mathworld.wolfram.com/GlobalOptimization.html for
other methods). But, If I was in your place, I'd just recognize that since it is possible to
have multiple yet equivelent optimal max-EV strategies, that it is (1) most probably the
case there are mulitple, yet equivalently optimal min-cost-royal or kelly-betting
strategies, etc, and (2) that therefore it is not necessarily true that "all other strategies are
non optimal".

···

--- In vpFREE@yahoogroups.com, Steve Jacobs <jacobs@x...> wrote:

You also didn't answer my question. Are you a physicist, or was
your reference to "Feynman path integrals" just tossed out as some
form of "name dropping"?

Steve (and anyone else who wants to chime in, of course ;), I have a question about how EV is computed for use in developing a strategy.
   
  As I understand it, EV for a given set of dealt and held cards is the *average* of all possible outcomes; that is, the total coins paid (in units) divided by the total number of possible hands. Developing a strategy is simply a matter of sorting all possible holds by descending EV.
   
  Aren't averages considered "brute force" values, statistically speaking? Shouldn't something like the "mean" and standard deviation (variance?) be used instead? That way, someone could calculate a proper strategy for them based on an acceptable variance level or value.
   
  A game I think is a good candidate for which to discuss an "alternate" (non-max EV) strategy is Multi-Strike (any other high-variance game would qualify as well). Lowering the variance without affecting the EV too much would be desirable for most people. As you have said, each person has their own parameters for what the "right" strategy is for them to use. For those lucky enough to have unlimited bankrolls, they probably don't care about variance and want max-EV. For the rest of us :wink: lowering the variance on some games is worth considering, as long as it has an acceptably small effect on EV. Others want to protect bankroll, etc.
   
  John

···

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John wrote:

Steve (and anyone else who wants to chime in, of course ;), I have a
question about how EV is computed for use in developing a strategy.

I'll accept that secondary invitation to chime in ... hopefully
intelligently, though likely not at authoritatively as Steve
might/will. EV, and variance, are hot buttons for me and prime
motivators in selecting plays.

  As I understand it, EV for a given set of dealt and held cards is
the *average* of all possible outcomes,

That's correct. You can look at the hand analysis in WinPoker and
Frugal VP to see this in action. For a given deal, a count is made of
all the possible winning hands on the draw, and their value
accumulated, for each of the 32 possible holds. The hold with the
highest EV wins as best.

Developing a strategy is simply a matter of sorting all possible
holds by descending EV.

It's much more difficult than that. The goal of a formal strategy is
to represent the possible holds for all conceivable dealt hands (2.6
mil for a non-wild card game) by a grouping of hold types (1 pair, 3
flush, etc.) and rank their value accordingly.

However, the value of each hold is dependent upon the discards in the
hand. Holding 3RF has weaker value if you're discarding a similarly
suited flush card than if not.

There are occasions where hold "A" is stronger than hold "B", when
they're contained in separately considered hands, but hold "B" is
stronger than "A" if they're contained in the same hand. These types
of considerations can pose complications when preparing a ranked
strategy table.

It's the case, for example, that some of the strategies in Frugal
Video Poker are more accurate than those in the prior released VP
Strategy Master, because these considerations (and others) are more
accurately reflected. (We're not talking about light-years of
improvement, but definitely not insignificant.)

Aren't averages considered "brute force" values, statistically
speaking? Shouldn't something like the "mean" and standard
deviation (variance?) be used instead? That way, someone could
calculate a proper strategy for them based on an acceptable variance
level or value.

Evaluating EV's is, at heart, a counting exercise and nothing more.
To the extent that values are expressed as averages, rather than
absolutes (both are valid), they reflect the same "brute force"
method. "Mean", as interpreted for vp analysis, has no practical
application beyond the weighted average value of possible holds -- a
straight arithmetic average.

Consideration of standard deviation/variance puts the analysis into an
entirely different framework -- one that's multivariate and requires
that the player make judgemental decisions.

Steve Jacobs has discussed various alternate strategies, each of which
has a different goal than the "Max-EV" that's reflected in almost all
published strategies. He has written a discussion on this topic that
can be found at:
http://members.cox.net/vpfree/FAQ_S.htm

  A game I think is a good candidate for which to discuss an
"alternate" (non-max EV) strategy is Multi-Strike (any other
high-variance game would qualify as well). Lowering the variance
without affecting the EV too much would be desirable for most
people.

I agree. As you say, any higher variance game is a potential
candidate for alternate strategies which decrease variance without
undue ER impact.

One factor is that for all but the more advanced players, the analysis
and playing considerations involved are almost esoteric when compared
to the challenge of just getting the basics down. Plus, there are no
ready made software tools to assist with this (although a good deal of
the legwork can be accomplished with modified vp software use,
augmented by a good spreadsheet program).

But, I'll offer up my personal perspective on this, which largely
isn't shared by Steve Jacobs:

If you set a tight tolerance on ER reduction, the extent to which you
can reduce the variance of most games is relatively nominal. I won't
suggest insignificant, since it's possible to shave as much as 10% of
the variance at the extreme in some cases.

However, more often than not, a game that presents an uncomfortable
variance play at a given bankroll isn't going to be made appreciably
more comfortable under an altered strategy to reduce variance. So,
I've largely lost interest in this area of game exploration and almost
entirely stick to Max-EV strategies.

As an example, I once sought to make a dent in 10/7 DB variance by
holding pat FH's over 3 Aces. The EV difference is very small, but
obviously this, in a single instance, makes a big variance reduction.
But, I ultimately decided that the relative ravages of this game over
gentler games such as JB and BP were such that the game wasn't any
more comfortable. In fact, the downside potential made me crave the
variance adding shot for a 800 cr. win instead of just taking a no
risk 50 cr. win.

But this is a personal take. The variance/ER tradeoff is one of
individual preference and to be decided by each player.

- Harry

> You also didn't answer my question. Are you a physicist, or was
> your reference to "Feynman path integrals" just tossed out as some
> form of "name dropping"?

While I don't consider myself a physicist, I have worked as one for few
years. (Does tht make me a "professional physicist?" ) My degree is in
Physical Chemistry, not Physics, and at one time I was an expert on some
obscure areas of quantum physics/optics. While I have never taught a
coarse on Feynman path integrals, I have covered that subject in other
classes I have taught. Perhaps ten years ago I could have handled (without
help) a renomalization problem using Feynman's approach, but not today. I
do know where to find the help I need if I had to solve such a problem
today, though.

Thank you, that gives me a better feel for your background. If discussing
things with you weren't such a tedious process, it would be interesting to
bounce some of my ideas off of you. Too bad.

But, I feel quite strongly that my qualifications (or lack
there-of) shouldn't matter to you.

They don't. But knowing what you've done and what you've studied
during your lifetime at least helps me to know what kind of terminology
I can use when attempting (however futilely) to discuss things with you.

Credentials don't tend to impress me, nor does a lack of credentials cause
me to assume that someone's ideas automatically lack merit. I'm willing to
learn new things from any source.

Rather than 'simply beleiving what I
say/write or not', I'd hope that you could convince yourself of things or
perhaps ask questions where you need help.

Do you think that I just pull these things out of nowhere without any
consideration for whether they are correct? You assume _way_ too
much.

Back to my point: IN GENERAL, OPTIMIZATION PROBLEMS CAN HAVE MORE THAN ONE
EQUIVALENTLY OPTIMAL SOLUTION OR NO SOLUTION.

I've conceded that multiple times, as you would recognize if you had
applied a modicum of reading comprehension to my posts. Yes, multiple
optimal solutions can happen. BFD. Move on.

In general, the
statement "that since X is an optimal solution to the problem, all other
solutions are non- optimal" just isn't true.

Fine. How does repeating this, over and over and over, after I've already
admitted that you were correct, help further the discussion?

You dick is bigger (to phrase things in _your_ terms). Can we move on now?

So either you just don't beleive these mathematical facts (if I may borrow
your usage) or you don't think it applies to your strategies.

If you go back and actually _read_ my posts, you might find this:

# Specific examples of multiple strategies have already been posted for
# max-EV. �I've never seen such an example for other types of strategies,
# but it isn't something that I spend much time looking for. �I believe they
# are about as likely to occur in alternate strategies as they are in max-EV
# strategies, because the method I use to find optimal strategies is based
# on maximizing "virtual EV" based on a "virtual payoff schedule."

Since you appear to need a map _and_ a flashlight to understand this,
let me help: First line: "Specific examples of multiple strategies have
already been posted for max-EV". See that? I said it happens, in real
games (not just theoretically, but in actually casino games, physical
machines).

As to non-max-EV strategies, I said right in the same paragraph: "I believe
they [multiple equivalent strategies] are about as likely to occur in
alternate strategies as they are in max-EV strategies..."

So, now you come along and claim that I think it doesn't apply to my
strategies? I can only conclude that you aren't actually paying attention
to what I write.

I could go
ahead and write a long tutorial on this subject, complete with references,
etc., trying (likely in vane) to persuade you otherwise. Or you could, I
guess, save me the effort, and show how I got the facts wrong or how they
don't apply to you.

I've tried to save you the effort. You didn't listen, because you're too
busy huffing and puffing to try to blow my house down. Get over yourself.

You might also show, through enumertion and
evaluation of all other posible strategies, that yours is indeed the only
optimal one, surely a painful if not imporssible task. (See
http://mathworld.wolfram.com/GlobalOptimization.html for other methods).

I've already used a more analytical approach to convince myself that
my strategies are in fact optimal. But, you are such a royal pain to discuss
anything with, that I'm completely disinclined to elaborate on that here.

But, If I was in your place, I'd just recognize that since it is possible
to have multiple yet equivelent optimal max-EV strategies, that it is (1)
most probably the case there are mulitple, yet equivalently optimal
min-cost-royal or kelly-betting strategies, etc, and (2) that therefore it
is not necessarily true that "all other strategies are non optimal".

Already conceded the point. Since it appears that your skills in reading
comprehension didn't allow you to recognize that fact, there is little more
that I can do to help you, unless you would like me to send you a map
and a flashlight (batteries not included).

I don't imagine this acknowledgement will satisfy you, any more than
previous ones have. I'm moving on. Reply if you like, to have the final
word, and I'll try very hard to ignore your post.

···

On Monday 12 December 2005 12:33 pm, cdfsrule wrote:

--- In vpFREE@yahoogroups.com, Steve Jacobs <jacobs@x...> wrote:

Steve (and anyone else who wants to chime in, of course ;), I have a
question about how EV is computed for use in developing a strategy.

  As I understand it, EV for a given set of dealt and held cards is the
*average* of all possible outcomes; that is, the total coins paid (in
units) divided by the total number of possible hands. Developing a strategy
is simply a matter of sorting all possible holds by descending EV.

As others have mentioned, "average" is an ambiguous term. EV is
based on the arithmetic mean of the possible outcomes from each
draw.

You could develop a strategy by sorting a list of all possible holds, but
the resulting strategy would be too complex to memorize, because the
distinct number of holds is generally quite large. For example, one
max-EV strategy for 9/6 JoB has 1292 unique holds that come into
play at some point. The trick for strategy developers is to reduce such
a list to a manageable size.

Aren't averages considered "brute force" values, statistically speaking?
Shouldn't something like the "mean" and standard deviation (variance?) be
used instead? That way, someone could calculate a proper strategy for them
based on an acceptable variance level or value.

Variance isn't a factor in max-EV strategy, only the arithmetic mean of the
outcomes that are made possible by each draw. As others have pointed out,
there are other types of "mean" that could be applied to find an optimal
strategy. Solving for geometric mean is mathematically equivalent to finding
a log-optimal strategy (which is approximated by "Kelly" strategy). I would
also claim that each type of optimization problem could be thought of as
leading to a corresponding "mean" that is unique to the quantity being
optimized, but I wouldn't be surprised if most statisticians would disagree
with that view.

  A game I think is a good candidate for which to discuss an "alternate"
(non-max EV) strategy is Multi-Strike (any other high-variance game would
qualify as well). Lowering the variance without affecting the EV too much
would be desirable for most people. As you have said, each person has their
own parameters for what the "right" strategy is for them to use. For those
lucky enough to have unlimited bankrolls, they probably don't care about
variance and want max-EV. For the rest of us :wink: lowering the variance on
some games is worth considering, as long as it has an acceptably small
effect on EV. Others want to protect bankroll, etc.

I believe Harry holds the view that a player with unlimited bankroll would
want max-EV strategy. My view is that a player who views EV as most
important to them would want max-EV strategy, regardless of the size of
his/her bankroll.

My view on variance has changed as a result of studying alternate
strategies. For the kinds of alternate strategies that I've studied, variance
in and of itself simply doesn't matter, and I've come to believe that this
will continue to be true unless one goes out of his/her way to explicity
include variance in the optimization problem. As long as the optimization
is based on the entire probability distribution for a single event, the result
will be exact without having to formulate the problem using variance or
any higher moments. All of the meaningful information is encoded in
the probability distribution for a single event.

Anyway, my view on variance is that it has surprisingly limited value
for optimizing alternate strategies. Also, minimizing variance isn't very
good for most games, because doing so often requires losing intentionally
so that the outcome can't fluctuate -- clearly an undesirable thing to do,
unless your specific goal is to burn your bankroll as quickly as possible.

···

On Monday 12 December 2005 03:04 pm, John wrote:

I'm going to elaborate a bit here, just to make sure "cdfsrule" knows that
I get his point. I'm going to push this to an extreme, just to try to be
as pedantic as possible (although I'm sure "cdfsrule" can outshine me
here, even with one frontal lobe tied securely behind his back.)

Consider any JoB non-bonus game where the payoff for quads does not
depend on the value of the "kicker". In such a game, when the initial
deal is quads, the player can either keep all five cards, or discard the
kicker and draw a new one. Either way the final outcome will be the
same, and the play will maximize EV.

Each rank of dealt quads has 48 possible kickers. One could decide to
discard the kicker only if it is the ace of spades, and keep the kicker for
any other draw. Technically, this would be a different strategy than
"always keep all 5 cards when dealt quads." The decision to keep or
discard the ace of spades as a kicker could also be refined to depend on
the rank of the quads. For example, one could discard the ace of spades
when the quads have rank 2 through 7, and keep the ace of spades when
the quads have higher rank.

Similar "strategy decisions" could be made independently for all 52 possible
kickers. Each card face can appear as a kicker for 12 different dealt quads,
and each case can be treated independently as a "strategy variation." This
leads to 12 * 52 = 624 independent situations where the player can
decide whether to keep or discard a kicker. Therefore, the total number
of different strategies that are possible based on this truly meaningless
set of decisions is 2^624 = 6.96173 x 10^187. This number is mind-
numbingly huge, and has 188 digits, but it is the exact number of
different equivalent strategies that come about because kickers don't
matter when paying 4/kind hands.

One could worry endlessly about this mind-numbingly huge number
of possible strategy variations, or one could recognize the concept
that "kickers don't matter" and note that the decision is of no real
consequence. We have a choice to view this as 624 distinct decisions
that lead to a virtually countless number of distinct strategies, are as
a single decision that we just don't care about kickers.

You can spend all of your time worrying about the kickers, or you can
cut through such crap and get down to the business of actually generating
optimal strategies for real VP games. I choose to cut through the crap
and generate strategies. If others wish to stress out endlessly about the
mathematical trivia, then it is no wonder that they never actually reach
the point where they can apply the math to a real game.

···

On Monday 12 December 2005 07:01 pm, Steve Jacobs wrote:

On Monday 12 December 2005 12:33 pm, cdfsrule wrote:

> Back to my point: IN GENERAL, OPTIMIZATION PROBLEMS CAN HAVE MORE THAN
> ONE EQUIVALENTLY OPTIMAL SOLUTION OR NO SOLUTION.

I've conceded that multiple times, as you would recognize if you had
applied a modicum of reading comprehension to my posts. Yes, multiple
optimal solutions can happen. BFD. Move on.

Steve Jacobs wrote:

Anyway, my view on variance is that it has surprisingly limited value
for optimizing alternate strategies. Also, minimizing variance isn't very
good for most games, because doing so often requires losing intentionally
so that the outcome can't fluctuate -- clearly an undesirable thing to do,
unless your specific goal is to burn your bankroll as quickly as possible.

A friend and I were debating over what the optimal strategy would be
if maximizing speed were the only goal. I first thought that it would
be to always redraw all 5 cards, since that takes the least time to
do, but he pointed out that that has the problem of how much time it
takes for the cards to be drawn. So perhaps the optimal strategy is
to always hold all 5 cards. Variance would even be indirectly
relevant, since hand-pays would be the most dreaded result. Who would
want to have a strategy that burns one's bankroll as quickly as
possible? Sheesh. A strategy that maximizes speed has a much less
negative EV and has the virtue of being much simpler.

--- In vpFREE@yahoogroups.com, Tom Robertson <thomasrrobertson@e...>
wrote:

A friend and I were debating over what the optimal strategy would be
if maximizing speed were the only goal. I first thought that it

would

be to always redraw all 5 cards, since that takes the least time to
do, but he pointed out that that has the problem of how much time it
takes for the cards to be drawn. So perhaps the optimal strategy is
to always hold all 5 cards. Variance would even be indirectly
relevant, since hand-pays would be the most dreaded result. Who

would

want to have a strategy that burns one's bankroll as quickly as
possible? Sheesh. A strategy that maximizes speed has a much less
negative EV and has the virtue of being much simpler.

That would work, I suppose, if the game automatically holds all
five cards. Otherwise, I think it's faster to do a redeal. I
suggest the best approach is to play at the 1-cent level (to avoid
hand pays) but hold losing hands to prevent the redeal from being a
better hand (because it takes time to increment the credit meter). I
wonder how many games one could play per hour with this strategy, on
a 1-cent hundred play machine?

Steve Jacobs <jacobs@x...> wrote:

"there is little more that I can do to help you, unless you would like me to send you a map
and a flashlight (batteries not included)."

Steve,

Great. I love gifts. Please send me the flashlight! Appearently I need it. Oh, need to tell
you tell you exactly where to send it. But wait... I'm not sure you are reading this. I've
read your posts over and over and I still can't tell if you are going to read this or not. After
all, didn't you write (in Message 52910) "I'll try very hard to ignore your post.". You didn't
say were going to read my post [this post] or not read it. Are you going to actually ignore
my post or just try to do so? I guess I need the flashlight AND the map.

So here's a recap (in case you are are reading). Perhaps I do need both your gifts. I've
struggled reading your responses to my posts. Over and over again you write about things
I didn't say, make unusual inferences, and simply get things I wrote wrong. I know I make
all kinds of mistakes when I write (& read), so I just figure you did the same. So, I just
chose to ignore what you have had to say when I didn't understand it, or when it seemed
incorrectly portray what I had to say, or was (seemingly) unrelated. But maybe I shouldn't
have done so? Perhaps (in the spirit of the flash light and map offerings), you might
explain some things for me?

Here is a recap of typical situation. There are plenty that go like this: In message 52719 I
wrote:

"For VP it is relatively simple, but for other games, like heads-up no-limit hold'em, the
optimal stratgey involves random play, and the distribution of that random play matters.
Really."

Note: I didn't suggest that you made any connection between VP and live poker,
nonetheless, you responded in 52791 with

"I have not made any claims whatsoever about applying these methods to live poker. That
is a whole different realm."

Why did you write what you did? I re-read your reponse carefully, over and over, and I just
couldn't come up with nice "explanation" for your response, so I ignored it... perhaps you
had just not read what I wrote carefully enough (and you listakening read something that
wasn't there?), or perhaps you were trying to discredit me? Were you just being overly
defensive? Were you simply refusing to think about what I had actually written and to
refusing to consider why I had written it?

As it turns out, I had put some though into my comment about heads-up poker. I was
bringing up a fundamental theorem of game theory, in a way I thought was non-
threatening. And interestingly, this theorem, which does not directly apply to VP, helps
explain my original point. I figured if I hit you over the head with it, you would just go on
one of your offsensive rants, tell me how wrong I was and force me to spend a lot of time
explaining something that has been excepted for some time (outside of VP). But here it is
now: In a zero-sum game (2 player), the optimal stratgey is a "mixed strategy" ( a
probabilistic linear combination of strategies). Now VP is NOT a zero-sum 2 player game.
But it has quantized (descritized) betting units. To be "optimal" certain strategies (like a
kelly-strategy) for VP would need to eploy a linear combination of "descritized" strategey
stratgeies (for simplicit, I will call this too a "mixed stratgey"). For example, suppose the
"optimal" strategy called for betting 7.5 unit, but you could only bet 5 or 10 units. Half
the time the player in situation should bet 5 units and half the time 10 units. Likewise, if
the play for the 5 or 10 units bets was different (it could be), it would vary in the same
proportion. In th infinite long run ( dare I invoke it), this kind of mixed stratgey would
always be found to be superior to any of the other stratgeies that always chose a fixed bet.
So why did I bring this up? I knew when I read you comment (the one I won't bother
repeating once again (don't want to cause you to try harder not to read my posts) granted
for this one, I had to assume that you didn't consider mixed-
stratgeies (of a sort), but I thought that was a reasonably good assumption. I also thought
you might ask me to explain my comment instead of rejecting it outright as unconneced
to VP. I was wrong. Please send the flashlight anyway.