vpFREE2 Forums

Long term vs short term again

This topic pops up from time to time. Part of the reason we keep discussing this is that there is no consensus on what 'long term' really means. I posted an article in the vpfree files section about long term a while ago. I think it is still there.

Harry brings up the point that different games have different 'long term' lengths.? Not only do you have to define the game, you have to define the meaning of long term.

In 9/6 JOB, the RF is only 2% of the return but is over 80% of the variance. If you take the royal out of the results, you get to the 'non royal long term' pretty quickly. The tremendous length of long term numbers comes from the royal contribution.

Let's say you play 403905 hands of JOB ( 10 royal cycles). If you are playing dollars, you have played $2,019,525 through the machine and your expected value is 0.995439 * $2,019,525 or -$9211.? Each RF away from your expected value of 10 has a tremendous affect on your results.?

43% of the time you will be more than 2 royals away from the expected value.? 27% of the time you will be more than 3 royals away from expected value.?

Bottom line is that unless you can predict how many royals you will get accurately, the long term is pretty darned long. And even after playing all these years, I can't predict how many royals I will get in a year.

···

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This topic pops up from time to time. Part of the reason we keep

discussing this is that there is no consensus on what 'long term'
really means. I posted an article in the vpfree files section about
long term a while ago. I think it is still there.

Harry brings up the point that different games have different 'long

term' lengths.? Not only do you have to define the game, you have to
define the meaning of long term.

In 9/6 JOB, the RF is only 2% of the return but is over 80% of the

variance. If you take the royal out of the results, you get to
the 'non royal long term' pretty quickly. The tremendous length of
long term numbers comes from the royal contribution.

Let's say you play 403905 hands of JOB ( 10 royal cycles). If you

are playing dollars, you have played $2,019,525 through the machine
and your expected value is 0.995439 * $2,019,525 or -$9211.? Each RF
away from your expected value of 10 has a tremendous affect on your
results.?

43% of the time you will be more than 2 royals away from the

expected value.? 27% of the time you will be more than 3 royals away
from expected value.?

Bottom line is that unless you can predict how many royals you will

get accurately, the long term is pretty darned long. And even after
playing all these years, I can't predict how many royals I will get
in a year.

Greek Johnny: Your last paragraph summarizes well. The long term is
very long for this game and you cannot predict royal flushes. Also
the game you play (J or B or DDB) has a big effect on trip results
and trip bankroll required let alone lifetime bakroll. In a bad
streak, you can easily go through $50K without ever being on the
positive side of the wager. Conversely you could get very lucky and
stop after a half hour's play and be very content with the results.
Denny_________________________________________________________________

···

--- In vpFREE@yahoogroups.com, greeklandjohnny@... wrote:
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greeklandjohnny wrote:

This topic pops up from time to time. Part of the reason we keep
discussing this is that there is no consensus on what 'long term'
really means.

I understand John's point, but I'd approach it a little differently:
"long term", as an isolated term, has little meaning. It's only in
the context of the probability that actual results will approach
expected results within some defined threshold of variance (as in "+/=
1%") that there's any true definition.

As he goes on to indicate, that tolerance has to be specified (as do
the game specifics being evaluated -- type, denomination, etc.) John
mentions his contribution to the VP FAQ on the subject -- it's an
intelligent offering: http://members.cox.net/vpfree/FAQ_LT.htm

One of the key weaknesses of the "long term" concept that he points
out is that even having played to the long term (under a given defined
threshold scenario), your exposure to an actual loss in dollar terms
generally proves to be rather immense.

He cites, by example, the calculations that were sourced from Tom Ski
in the general FAQ on this topic (it's possible that John's numbers
were calculated independently): Playing 10/7 DB, for a 95% confidence
that results will fall within 1% of expectation, a little over 1
million hands of play are required. For a tolerance of only a 0.1%
variance, over 10 millions hands must be played.

Under either long term definition (a tolerance for a 1% deviation, or
the more restrictive .1%), a shortfall of over 50,000 coins from
expected ending cash balance is within that tolerance. Whether
quarters, dollars, or whatever, that's a poor sense of comfort.

···

------

Surprisingly, that's seldom the angle from which critics of "advantage
play" approach their arguments. They argue that traditional
definitions of the "long term" simply aren't realistically achieved in
play.

They, of course, rely upon a nebulous concept of "long term", for with
many low to medium variance games (such as Jacks, DB, Deuces) a
long-term defined as a 1% variance tolerance is well within the realm
of an active player during their lifetime of play.

But whether the criticism is based upon the length of the "long term",
or the magnitude of the actual variance a player is exposed to once
the "long term" is reached, there's a very effective comeback in
support of the advantage play approach that should dismiss any
concern on these counts in the mind of someone approaching the subject
rationally.

I suggest that few, if any, players contemplating advantage play are
terribly concerned with how closely results approximate expected
results. They simply want reasonable assurance that over the long
haul they won't be subject to undue losses -- and ideally achieve
better than breakeven in their play.

"nightoftheiguana" (aka NOTI or "iggy") introduced the concept of "NO"
some time ago in this forum. NO represents the number of hands that
must be played for a player to have strong expectation (84%) of
positive results. This is a measure of the "long term" that is much
more practical than one defined by a variance from expected results.
And for the player who assiduously strives for a significant advantage
in their play (say, a 10/7 DB who plays with a minimum of .5% in
cb/bonus, or a 9/6 Jacks player that seeks a minimum threshold of .8%
in cb/bonus for play), such a "long term" can be surprisingly short.

As noted in the FAQ on the subject, NO is calculated as: var/((er-1+cb)^2)

So, for 10/7 DB + .5% (with a variance of 28), NO is 625 thou hands.
For 9/6 Jacks + .8%, NO is 800 thou hands.

To put these numbers in perspective, an active Jacks player who plays
800 hands per hour, 5 hours per week, would achieve NO expectation
within 4 years. The same would be true of a couple who play 10-12
hours each monthly.

And consider the FPDW player w/ .2 cb: NO = a mere 252 thou hands.

I find these numbers place the "long term" into a realm that serious
players should consider far from an abstract concept.

- Harry

Also, if you're more the visual type, run this Java calculator:
http://www.lotspiech.com/poker/GamblersRuin.html
Try stake $3000, retire with $8000 and game is Deuces Wild and hit
run. Grab some java and watch the future predicted with the magic of
mathematics. Then if you want to, go try it in the real world. The
question is: Do you feel lucky, punk? (Remember? Dirty Harry?)

···

--- In vpFREE@yahoogroups.com, "Harry Porter" <harry.porter@...> wrote:

And consider the FPDW player w/ .2 cb: NO = a mere 252 thou hands.

I find these numbers place the "long term" into a realm that serious
players should consider far from an abstract concept.

http://www.lotspiech.com/poker/GamblersRuin.html

Another good one to try on the above calculator is 4700 Jacks or
Better, since it's about a breakeven game. Try stake $5000 and retire
$6000. In the short term odds are about 3 to 1 against beating this
game. Eventually as you play the odds even out. When you get to
150,000 hands, there is only a 29% chance of being within a royal of
breakeven (-$1000 to +$1000 on quarters). Most people expect to
breakeven at this game, but the more hands you play, the less likely
is that result. The odds are more like 50-50 that you will either bust
out a total loss or the casino will kick you out for winning too much
(the odds are actually the ratio of these two end limits, if they are
the same it is 50-50). Most people would consider a 50% risk of ruin
to be excessive, to reduce it you'll have to find an edge against the
casino.

nightoftheiguana2000 wrote:

> And consider the FPDW player w/ .2 cb: NO = a mere 252 thou hands.
>
> I find these numbers place the "long term" into a realm that
> serious players should consider far from an abstract concept.

Also, if you're more the visual type, run this Java calculator:
http://www.lotspiech.com/poker/GamblersRuin.html
Try stake $3000, retire with $8000 and game is Deuces Wild and hit
run. Grab some java and watch the future predicted with the magic of
mathematics. Then if you want to, go try it in the real world. The
question is: Do you feel lucky, punk? (Remember? Dirty Harry?)

Excellent (actually, downright beautiful) suggestion.

Remember that without cashback, FPDW NO = 447,275. (Again, NO is the
point at which 84% of results can be expected to be positive.)

Allow some patience and let the calculator run to that point (for an
hour or two in the background, while you carry on with your "real"
work) to test how this percentage bears out. (You may wish to use the
stake/retire values of 4500/12000 if you decide to continue with the
second exercise proposed below.) I haven't performed this run yet --
I'll likely give it a go later today to satisfy my own curiosity.

A second exercise: Stop the calculator at that point and calculate
your expected win should you end with a positive result, and expected
loss should you end in the red. You do this by multiplying the
average value of each band by its probability and summing the result.

With an 84% chance of ending at the greater-magnitude expected win,
you'll likely consider your gaming prospects quite favorable.

(Note, if you multiply each value by its respective probability -
84%/16% - and sum the result, you should end with a value in the
ballpark of the EV of this play: (1.00762-1)*(477275*1.25)= approx
$4500. The $4500/$12000 stake/retire I suggest above will yield a
result that is closer to this value than the rougher $3000/$8000.)

···

--- In vpFREE@yahoogroups.com, "Harry Porter" <harry.porter@> wrote:

------

These exercises are as strong a validation of the principals of
advantage play as I can imagine. Those who reject advantage play tend
to be blind to such results.

(This is not to say that there aren't reasonable alternative
strategies for play other than max-EV that fully recognize the
underlying math of max-EV play. The VPFree write up on Video Poker
Strategies (authored by Steve Jacobs) describes some:
http://members.cox.net/vpfree/FAQ_S.htm
Note: For several of these, I consider the consequences vs. those of
Max-EV expected results to be of such limited magnitude, given the
preferences of most players, that there is limited, if any, benefit in
them.)

Of course, give the calculator a run under a thinner edge (say, 10/7
DB with no cb, and the inherent pitfalls of near B/E play become
apparent. (Similar risks race those who might play 9/6 Jacks w/ .6%
cb/bonus incentive, "secure" that they have an edge). Concerns become
greater when error cost (due to skill deficiencies,
inattention/distraction, etc.) is factored. There's often an
impression in AP writings (casual and in print) that any edge makes
for a strong play.

------

As a side note, I give credence that there are those for whom max-EV
strategies aren't appropriate -- notably, those who don't have
patience for the math to play out before having a strong probability
of achieving a given win goal. Alternate strategies, such as that
roughly outlined by Rob Singer, can be appropriate in such a case --
provided there's a strong cognizance of the underlying loss risk
(something GREATLY downplayed in his discussions).

I come under criticism (in a rather bizarre manner) from those who
find such a suggestion objectionable. (I won't go as far as to
suggest that bizarreness takes on a "goose stepping" guise, of course
:wink: -- any discussion of this latter remark is best suited for the
FREEvpFREE forum.)

- Harry

To my knowledge no one has stated these kind of "alternate strategies"
are "objectionable". The claims surrounding them are the problem. It
appears you need to get your facts straight.

Dick

···

--- In vpFREE@yahoogroups.com, "Harry Porter" <harry.porter@...> wrote:

As a side note, I give credence that there are those for whom max-EV
strategies aren't appropriate -- notably, those who don't have
patience for the math to play out before having a strong probability
of achieving a given win goal. Alternate strategies, such as that
roughly outlined by Rob Singer, can be appropriate in such a case --
provided there's a strong cognizance of the underlying loss risk
(something GREATLY downplayed in his discussions).

I come under criticism (in a rather bizarre manner) from those who
find such a suggestion objectionable. (I won't go as far as to
suggest that bizarreness takes on a "goose stepping" guise, of course
:wink: -- any discussion of this latter remark is best suited for the
FREEvpFREE forum.)

Two games compared:

9/6 Double Double Bonus:

1 hand = 55.28/11.28 = 4.9 to 1 against winning.

N0 = 42/-.01/-.01 = 420,000 hands, at which point, since this is a
negative expectation game, the odds are about 84/16 = 5.25 to 1
against winning. At 4N0 = 1.7 million hands, the odds are about 98/2 =
49 to 1 against winning.

15/9/5 Deuces Wild:

1 hand = 54.69/16.84 = 3.3 to 1 against winning.

N0 = 25.8/.0076/.0076 = 446,676 hands, at which point, since this is a
positive expectation game, the odds are about 84/16 = 5.25 to 1
against losing. At 4N0 = 1.8 million hands, the odds are about 98/2 =
49 to 1 against losing.

The low point looks like about at 500 hands with 65/35, about 2 to 1
against. 50/50 is reached at about 10,000 hands. At 10,000 hands I get
an average loss of about $400 (~3%), so the average win must be about
$400 + 2 x 10,000 x 1.25 x .0077 = about $590 (~5%). 0.5 x -$400 + 0.5
x $590 = $95.

···

--- In vpFREE@yahoogroups.com, "Harry Porter" <harry.porter@...> wrote:

You may wish to use the
stake/retire values of 4500/12000 if you decide to continue with the
second exercise proposed below.