Let's see if we can figure out how likely this is. If I'm wrong I hope
one of the other recreational probability theorists will correct me.
You can draw one more to the royal by flopping one of the cards you
need first AND drawing a blank on the second, OR flopping a blank
first AND getting one of the needed cards second. The probability of
the first event is
(2/47)*(45/46) = (90/2162)
The probability of the second is
(45/47)*(2/46) = (90/2162)
and adding them together the probability of getting exactly one more
is (180/2162)=8.33%, or odds of 11:1 against. That doesn't seem too
unlikely to me.
By the same reasoning the probability of getting two blanks is
(45/47)*(44/46)=91.58% and the probability of making your royal is
(2/47)*(1/46)=0.09%. As a sanity check add all those together and they
add up to 100%.
I may not be counting this right, but I get about a 1 in 30 chance of
being dealt 3 to a royal. If you're seeing three to a royal dealt
about 20 times an hour you'd expect to get one more once or twice an
hour on the draw.
Mike
···
--- In vpFREE@yahoogroups.com, "lizurdlips" <lizurdlips@...> wrote:
Does anyone notice this:
While holding three cards to the royal the redraw delivers one of the
cards needed but not the other. This seems to happen quite often.