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double bonus Q

Assuming perfect play you can expect to average one royal per 48,048 hands, so in 1,019,200 hands you can "expect" 21 royals.

The Poisson distribution, however, can give much more interesting information. Under those same circumstances, you have about a 99.5% chance of more than ten royals.

Dan

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"bishqqq" <bishqqq@yahoo.com> wrote:

        OK....another question....i estimated that i've played
1,019,200 hands of quarter double bonus the last 3 years..... how
many royals, on average, should i get on a million hands.....thnx

--
Dan Paymar, author of "Video Poker - Optimum Play"
Editor and publisher of "Video Poker Times" newsletter
Visit my web site at www.OptimumPlay.com

"Chance favors the prepared mind"
- Louis Pasteur

The normal approximation gives the following:
expected number of royal = 1019200/48048= 21.2121
the approx probability of 11 or more royals is .989989547

Dale Borowiak

"bishqqq" <bishqqq@y...> wrote:
> OK....another question....i estimated that i've played
>1,019,200 hands of quarter double bonus the last 3 years..... how
>many royals, on average, should i get on a million hands.....thnx

Assuming perfect play you can expect to average one royal per

48,048

hands, so in 1,019,200 hands you can "expect" 21 royals.

The Poisson distribution, however, can give much more interesting
information. Under those same circumstances, you have about a

99.5%

···

--- In vpFREE@yahoogroups.com, Dan Paymar <Dan@O...> wrote:

chance of more than ten royals.

Dan

--
Dan Paymar, author of "Video Poker - Optimum Play"
Editor and publisher of "Video Poker Times" newsletter
Visit my web site at www.OptimumPlay.com

"Chance favors the prepared mind"
- Louis Pasteur

Dale, would you accept an exact value of 0.988438106?

For those who would like to be able to do this calculation on their
own, I believe the appropriate Excel method is with the Binom
function as follows: 1-BINOMDIST(F25,G25,H25,TRUE) where F25 = the
number of royals, G25 = the number of hands and H25= the prob of
getting a royal in one hand. The "True" variable says you want the
number of royals to be treated as a minimum number rather than
absolute. In other words, true= 11 or more royals and false = exactly
11, no more no less.

Now, what they are saying is with the odds of getting 11 or more at
about 98.84%, the odds of getting only 10 or fewer is 1.16%, and in
VP 1% odds come through all the time (that's the odds of getting a
full house).

But, of course, he didn't say he got 11 royals. He said he got 6. I
suppose Dan was looking at a chart rather than doing the calculation
himself and the chart didn't list the value for 6. But if you
calculate it out, 6 is much less believeable than 10: the prob is
0.99965903. That means, if he really played over a million hands, the
odds of getting 6 or fewer royals is only 0.03% or approximately 1 in
2931. Now, that's still possible because even long odds come through
once in a while, but that's a lot harder to believe.

That is part of why I believe the number of hands must be overstated
at one million, because the odds of getting less than 7 royals in a
million hands is 2930-to-1 against, while in 500,000 hands the odds
of fewer than 7 are only 4.4-to-1 against (those with excel, run that
same formula with 500K hands, then 600K, then 700K, etc), a much more
reasonable proposition. A million is certainly possible, but
something less is far more likely.

···

--- In vpFREE@yahoogroups.com, "rosspark100" <rosspark100@h...> wrote:

The normal approximation gives the following:
expected number of royal = 1019200/48048= 21.2121
the approx probability of 11 or more royals is .989989547

Dale Borowiak