vpFREE2 Forums

Closest 50/50 bet in a casino? There might be a good comp play h

#1

I haven't followed this thread closely and am too lazy togo to read past posts. However, one way is to betpass and have a partner (must keep that info away from thefloor person) bet don't pass for the same amount.
There still is a chance of a loss on the don't pass becauseeither a 2 or 12 is usually a push and so the pass bet willlose. Can cut those losses by betting the 2 and 12 or thecraps.
Does this answer your question?

···

--- On Fri, 6/5/09, Barry Glazer <b.glazer@att.net> wrote:

From: Barry Glazer <b.glazer@att.net>
Subject: [vpFREE] Re: Closest 50/50 bet in a casino? There might be a good comp play h
To: vpFREE@yahoogroups.com
Date: Friday, June 5, 2009, 1:52 PM

      > 11c. Re: Closest 50/50 bet in a casino? There might be a good comp play h

Posted by: "Dennis Salguero" salguero@gmail. com

Date: Thu Jun 4, 2009 5:18 pm ((PDT))

No, no, you guys are not understanding this properly. I can play BOTH red &

black on the SAME spin and get points on all my "coin in". Even with double

zero, playing both sides of black/red can't be an edge of 5.26%

Can too. Even with my statistical alzheimer's I remember enough to do this one.

18 red numbers, 18 black numbers, 2 zeroes, 38 possibilities, you lose both red and black 2/38 times = 0.0526 = 5.26%, break even the rest of the time. There are worse bets in roulette (I don't know what they are because I don't play), but no combination of bets will reduce the house edge to less than 5.26%. Single zero wheel, cut the house edge approx. in half.

Doesn't matter if you bet only red, only black, or both, odds are the same (except by betting both you guarantee you never win anything even if you're lucky and never hit a zero - of course, you also guarantee you never lose anything UNLESS you hit a zero -- but the point is, the zeroes are on the wheel and you'll hit one or the other 5.26% of the time, long term).

--BG

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[Non-text portions of this message have been removed]

#2

Yes, thats getting closer. In my scenario though, I'm using an electronic
version of craps, so there's no need for "cover" from the floor person, it
racks up the same number of points because its views it as "coin in"
regardless of where its put on the spread . . . see where I'm going with
this? :slight_smile:

Looking at the information from other folks, it looks like the pass/dont
pass will give me the best odds at racking up points.

D

···

On Fri, Jun 5, 2009 at 2:27 PM, george lee <glee4ever@yahoo.com> wrote:

I haven't followed this thread closely and am too lazy togo to read past
posts. However, one way is to betpass and have a partner (must keep that
info away from thefloor person) bet don't pass for the same amount.
There still is a chance of a loss on the don't pass becauseeither a 2 or 12
is usually a push and so the pass bet willlose. Can cut those losses by
betting the 2 and 12 or thecraps.
Does this answer your question?

--- On Fri, 6/5/09, Barry Glazer <b.glazer@att.net <b.glazer%40att.net>> > wrote:

From: Barry Glazer <b.glazer@att.net <b.glazer%40att.net>>
Subject: [vpFREE] Re: Closest 50/50 bet in a casino? There might be a good
comp play h
To: vpFREE@yahoogroups.com <vpFREE%40yahoogroups.com>
Date: Friday, June 5, 2009, 1:52 PM

> 11c. Re: Closest 50/50 bet in a casino? There might be a good comp play h

> Posted by: "Dennis Salguero" salguero@gmail. com

> Date: Thu Jun 4, 2009 5:18 pm ((PDT))

>

> No, no, you guys are not understanding this properly. I can play BOTH red
&

> black on the SAME spin and get points on all my "coin in". Even with
double

> zero, playing both sides of black/red can't be an edge of 5.26%

>

Can too. Even with my statistical alzheimer's I remember enough to do this
one.

18 red numbers, 18 black numbers, 2 zeroes, 38 possibilities, you lose both
red and black 2/38 times = 0.0526 = 5.26%, break even the rest of the time.
There are worse bets in roulette (I don't know what they are because I don't
play), but no combination of bets will reduce the house edge to less than
5.26%. Single zero wheel, cut the house edge approx. in half.

Doesn't matter if you bet only red, only black, or both, odds are the same
(except by betting both you guarantee you never win anything even if you're
lucky and never hit a zero - of course, you also guarantee you never lose
anything UNLESS you hit a zero -- but the point is, the zeroes are on the
wheel and you'll hit one or the other 5.26% of the time, long term).

--BG

============ =====

[Non-text portions of this message have been removed]

[Non-text portions of this message have been removed]

#3

I don't know this for a fact, but aren't strict pass/no pass bettors
poorly rated by the pit? Everyone knows it's a low theo bet.

#4

George, the original pass line bet has a house advantage of 1.41%. Regardless of what else you bet, that particular wager has a house advantage of 1.41%. If you take 10 times odds, the 10 times odds bet has a 0 house advantage but the original wager has a house edge of 1.41%.

Let's say you bet $10 on the pass line and your buddy bets $10 on the don't pass line. You roll a 4. You now put up a $100 odds bet and your buddy puts up a $200 odds bet on the don't. You each have an expected loss of $0.14. If you don't take the odds bets, you each have an expected loss of $0.14 on those pass line and don't pass bets. If you each bet the field or no craps , the pass line and don't pass line bets each have an expected loss of $0.14. Making other bets doesn't change the odds of your initial pass line bet.

You're not cutting the losses of the original bet. In the case of the 2 and 12, you are making a negative expectation bet that has a different win/loss pay off than the odds bet but it does not 'cut the losses' of the original bet.

Why should a casino care if 2 people make opposing pass line and don't pass bets? Each one is playing a -1.41% bet. If 2 different people make those bets, the house doesn't care. Why should it care if 2 friends do it? They are both risking their money against the house edge. In fact, a casino should encourage that behavior on any negative expectation wager. Bets with match plays are a little different but same principal holds. A casino that encourages you to play 2 match plays on the pass line but discourages you from playing one match play on pass line and one on the don't pass line doesn't really understand how match plays work. I am talking about cases where a husband and wife each have a match play, not the cases where Joe hustler has 17,000 match plays and is trying to reduce his variance as much as possible.

···

--- In vpFREE@yahoogroups.com, george lee <glee4ever@...> wrote:

I haven't followed this thread closely and am too lazy togo to read past posts. However, one way is to betpass and have a partner (must keep that info away from thefloor person) bet don't pass for the same amount.
There still is a chance of a loss on the don't pass becauseeither a 2 or 12 is usually a push and so the pass bet willlose. Can cut those losses by betting the 2 and 12 or thecraps.
Does this answer your question?

--- On Fri, 6/5/09, Barry Glazer <b.glazer@...> wrote:

#5

You can often find doey-don't, partner play and the like disucssed with varying degrees of thoroughness at rec.gambling.craps on the usenet.

george lee wrote:

···

I haven't followed this thread closely and am too lazy togo to read past posts. However, one way is to betpass and have a partner (must keep that info away from thefloor person) bet don't pass for the same amount.
There still is a chance of a loss on the don't pass becauseeither a 2 or 12 is usually a push and so the pass bet willlose. Can cut those losses by betting the 2 and 12 or thecraps.
Does this answer your question?

--- On Fri, 6/5/09, Barry Glazer <b.glazer@att.net > <mailto:b.glazer%40att.net>> wrote:

From: Barry Glazer <b.glazer@att.net <mailto:b.glazer%40att.net>>
Subject: [vpFREE] Re: Closest 50/50 bet in a casino? There might be a good comp play h
To: vpFREE@yahoogroups.com <mailto:vpFREE%40yahoogroups.com>
Date: Friday, June 5, 2009, 1:52 PM

> 11c. Re: Closest 50/50 bet in a casino? There might be a good comp play h

> Posted by: "Dennis Salguero" salguero@gmail. com

> Date: Thu Jun 4, 2009 5:18 pm ((PDT))

>

> No, no, you guys are not understanding this properly. I can play BOTH red &

> black on the SAME spin and get points on all my "coin in". Even with double

> zero, playing both sides of black/red can't be an edge of 5.26%

>

Can too. Even with my statistical alzheimer's I remember enough to do this one.

18 red numbers, 18 black numbers, 2 zeroes, 38 possibilities, you lose both red and black 2/38 times = 0.0526 = 5.26%, break even the rest of the time. There are worse bets in roulette (I don't know what they are because I don't play), but no combination of bets will reduce the house edge to less than 5.26%. Single zero wheel, cut the house edge approx. in half.

Doesn't matter if you bet only red, only black, or both, odds are the same (except by betting both you guarantee you never win anything even if you're lucky and never hit a zero - of course, you also guarantee you never lose anything UNLESS you hit a zero -- but the point is, the zeroes are on the wheel and you'll hit one or the other 5.26% of the time, long term).

--BG

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