Two related questions here first, what's the formula to calculate
risk of ruin (and thus bankroll) for a given game and desired risk
level? I presume it's based on a game's ER, variance and acceptable
risk level?
Second question is more involved and more philosophical is there a
better way to measure a game's riskiness than Variance?
Here are the problems I have with variance:
1. Highly degree of dependence on a single high term. For example,
take the relatively low-variance 9/6 jacks-or-better game (19.50 for
the basic game) and add a high (say 200% of reset) progressive
jackpot. The result is a variance number of 67.00 for the game, which
is higher than most of the high variance basic games (Triple Bonus,
Super Aces, etc). Yet it still plays like normal JOB as long as you
don't hit the royal, very small swings, little threat of massive loss.
2. Game return irrelevant. The variance calculation doesn't factor in
game return. Thus, 9/6 JOB with 0.5% cashback has a variance of 19.5
and a return of 100%, while 6/5 JOB at the same casino has a variance
of 19.0 and return of 95%. Which is more of a risk to your bankroll?
And while the answer to that question is obvious on its face, it
might not be so obvious comparing Super Double Bonus (var 38, er
100.10) to Super Aces (var 63, er 100.35).
By the way, I'm not doubting the correctness of the Variance
calculation or the truth of what it is saying. Your final return
playing 200% progressive JOB truly will be as various, as defined by
that ratio, as SAB. If you were to run a trial of 10,000 sessions of
10,000 hands of each game, the final results would calculate out to
similar standard deviations. However, I believe the clustering
patterns would be different SAB would show many more big losers and
more big winners, while 200% JOB would show a lot of small losers and
a handful of extremely big winners. Just because they average out to
the same standard deviation does not mean they are equally risky.
Furthermore, the JOB group will total a much larger net win due to
the ER advantage.
So, what's a formula that shows a satisfactory result in this
intuitive case, that can be applied to other cases that are not so
intuitive?