I ran into something interesting while playing "reduced pay deuces wild" with the following payoff table (to 1, with 5 coins in):
RF: 800
4D: 200
WR: 25
5K: 15
SF: 9
4K: 4
FH: 4
FL: 3
ST: 2
3K: 1
Dealt: 2S, 2C, JS, JD, 10S
It turns out that the E.V. of 4.9362 is identical for discarding either the 10S or the JD!
This is so surprising that I made a hand calculation:
Discarding the 10S:
4 cards will give a 5K, and 43 cards a 4K
(4*15 + 43*4) / 47 = 232/47 = 4.9362
Discarding the JD:
5 cards will get a WR; 3 for a SF; 6 for a 4K; 4 for a FL;
18 for a ST; and 12 for a 3K
(5*25 + 3*9 + 5*4 + 4*3 + 18*2 + 12*1) / 47 = 232/47 = 4.9362
Question: Is there any "volatility" issue here that would decide the better discard?
Or is this really a flat-ass tie?
(As it happened, I discarded the JD and drew a deuce for the wild royal.)
Note: For the "full pay" deuces wild payout schedule, there is no tie.
Discard the 10: EV = 5.8511
Discard the JD: EV = 4.9574
- - Norma