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Ace Invaders Quiz

#1

O.K., all you math wizards out there will love this one.

What would be the chances of getting the best NON-ROYAL hand in Ace
Invaders? That, of course, would be Four Aces on the top line,
dropping to create Five Aces on the bottom two lines. Keep in mind
that the "fifth" ace on the second line has to be in the right
position to not duplicate one of the "falling" four aces. The bottom
line is obviously irrelevant - the five aces above simply fall.

Any odds on this?

#2

In Ace Invaders, the chances of being dealt a four of a kind on the
top row is 1 in 4165 games. The chances that the four of a kind is
Aces is 1 in 13 therefore the chances of being dealt four aces
(4165x13=54145). Actually this is true for any specifically dealt
four of a kind in any five card poker game.

Now that we know that getting four aces dealt in a poker game is 1 in
54,145 we need to know the chances of getting an Ace in the
appropriate position on the second hand. This one is easy because
there is no correlation between the two hands. The chances of getting
an Ace in any specific position is 1 in 13.

So the answer to your question is: 54,145 x 13 = 703,885 games.

David

···

--- In vpFREE@yahoogroups.com, "npf125" <nps125@m...> wrote:

O.K., all you math wizards out there will love this one.

What would be the chances of getting the best NON-ROYAL hand in Ace
Invaders? That, of course, would be Four Aces on the top line,
dropping to create Five Aces on the bottom two lines. Keep in mind
that the "fifth" ace on the second line has to be in the right
position to not duplicate one of the "falling" four aces. The bottom
line is obviously irrelevant - the five aces above simply fall.

Any odds on this?

#3

David correctly answered the Ace Invaders Quiz for the top two lines
--- except he forgot to exclude royal flushes. The aces only fall down
to lower lines if they would improve the hand. If a royal flush were
dealt on the second hand, even with the ace in the correct position, the
aces would not fall down. And even if we avoided that problem, a dealt
royal on the bottom line would also kill the deal.

    Once you remember to take those pesky dealt royals into
consideration, the answer is not difficult.

Bob Dancer

For the best in video poker information, visit www.bobdancer.com
or call 1-800-244-2224 M-F 9-5 Pacific Time.

···

-----Original Message-----
From: vpFREE@yahoogroups.com [mailto:vpF…@…com] On Behalf
Of drich295
Sent: Thursday, December 29, 2005 12:53 PM
To: vpFREE@yahoogroups.com
Subject: [vpFREE] Re: Ace Invaders Quiz

In Ace Invaders, the chances of being dealt a four of a kind on the
top row is 1 in 4165 games. The chances that the four of a kind is
Aces is 1 in 13 therefore the chances of being dealt four aces
(4165x13=54145). Actually this is true for any specifically dealt
four of a kind in any five card poker game.

Now that we know that getting four aces dealt in a poker game is 1 in
54,145 we need to know the chances of getting an Ace in the
appropriate position on the second hand. This one is easy because
there is no correlation between the two hands. The chances of getting
an Ace in any specific position is 1 in 13.

So the answer to your question is: 54,145 x 13 = 703,885 games.

David
--- In vpFREE@yahoogroups.com, "npf125" <nps125@m...> wrote:

O.K., all you math wizards out there will love this one.

What would be the chances of getting the best NON-ROYAL hand in Ace
Invaders? That, of course, would be Four Aces on the top line,
dropping to create Five Aces on the bottom two lines. Keep in mind
that the "fifth" ace on the second line has to be in the right
position to not duplicate one of the "falling" four aces. The bottom
line is obviously irrelevant - the five aces above simply fall.

Any odds on this?

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#4

To be precise, a *drawn* Royal Flush on the bottom line would also
kill the deal but that ~54000 frequency is a great approximation.

-Larry DeMar
President
Leading Edge Design
http://www.ledgaming.com

···

--- In vpFREE@yahoogroups.com, "Bob Dancer" <bob.dancer@c...> wrote:

    David correctly answered the Ace Invaders Quiz for the top two lines
--- except he forgot to exclude royal flushes. The aces only fall down
to lower lines if they would improve the hand. If a royal flush were
dealt on the second hand, even with the ace in the correct position, the
aces would not fall down. And even if we avoided that problem, a dealt
royal on the bottom line would also kill the deal.

    Once you remember to take those pesky dealt royals into
consideration, the answer is not difficult.

Bob Dancer

For the best in video poker information, visit www.bobdancer.com
or call 1-800-244-2224 M-F 9-5 Pacific Time.

-----Original Message-----
From: vpFREE@yahoogroups.com [mailto:vpF…@…com] On Behalf
Of drich295
Sent: Thursday, December 29, 2005 12:53 PM
To: vpFREE@yahoogroups.com
Subject: [vpFREE] Re: Ace Invaders Quiz

In Ace Invaders, the chances of being dealt a four of a kind on the
top row is 1 in 4165 games. The chances that the four of a kind is
Aces is 1 in 13 therefore the chances of being dealt four aces
(4165x13=54145). Actually this is true for any specifically dealt
four of a kind in any five card poker game.

Now that we know that getting four aces dealt in a poker game is 1 in
54,145 we need to know the chances of getting an Ace in the
appropriate position on the second hand. This one is easy because
there is no correlation between the two hands. The chances of getting
an Ace in any specific position is 1 in 13.

So the answer to your question is: 54,145 x 13 = 703,885 games.

David
--- In vpFREE@yahoogroups.com, "npf125" <nps125@m...> wrote:
>
> O.K., all you math wizards out there will love this one.
>
> What would be the chances of getting the best NON-ROYAL hand in Ace
> Invaders? That, of course, would be Four Aces on the top line,
> dropping to create Five Aces on the bottom two lines. Keep in mind
> that the "fifth" ace on the second line has to be in the right
> position to not duplicate one of the "falling" four aces. The bottom
> line is obviously irrelevant - the five aces above simply fall.
>
> Any odds on this?
>

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<http://groups.yahoo.com/gads?t=ms&k=Online+gambling&w1=Online+gambling&
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10QO5nvjXwYPuAFZkkXhg> gambling Outdoor
<http://groups.yahoo.com/gads?t=ms&k=Outdoor+recreation&w1=Online+gambli
ng&w2=Outdoor+recreation&w3=Recreation+software&w4=Gambling&c=4&s=84&.si
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oor+recreation&w3=Recreation+software&w4=Gambling&c=4&s=84&.sig=0BcqyN86
pav5YYeEn1BCYw>

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