There are 235 combinations of 4RF for each RF. This does not mean you
will end up with all of them between every RF but does give a little
sanity to the odds.
To get this number you simply replace each card in the RF with any of
the other 47 cards. You do this for each card A,K,Q,J,T. So you end up
with 47*5 = 235 possible combinations. Another interesting final hand
is a 4RF straight. In this case each of the 5 cards can be replaced
with the corresponding other 3 cards. This yields 5*3 = 15 times.
The reason you don't end up with them all is that you don't hold cards
to maximize these possibilities. 90-92 seems reasonable to me.
Dick
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--- In vpFREE@yahoogroups.com, Victoria Rosado <ros4144@y...> wrote:
That's true, 1 of 47 when you are dealt 4 to a royal
but I think the question was how often you end up with
4 to a royal. So you must add all those times you
kept 1,2, or 3 to a royal and ended up with 4, so the
90-92 might be right but seems a little low to me.
Victoria